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f(n)=415nf(n)=41-5n\newlineComplete the recursive formula of f(n)f(n).\newline f(1)=f(1)=\square \newlinef(n)=f(n1)+f(n)=f(n-1)+\square

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Q. f(n)=415nf(n)=41-5n\newlineComplete the recursive formula of f(n)f(n).\newline f(1)=f(1)=\square \newlinef(n)=f(n1)+f(n)=f(n-1)+\square
  1. Find First Term: Find the first term of the sequence.\newlineTo find the first term, we substitute n=1n = 1 into the function f(n)=415nf(n) = 41 - 5n.\newlinef(1)=415(1)=415=36f(1) = 41 - 5(1) = 41 - 5 = 36
  2. Find Second Term: Find the second term of the sequence to observe the pattern.\newlineSubstitute n=2n = 2 into the function f(n)=415nf(n) = 41 - 5n.\newlinef(2)=415(2)=4110=31f(2) = 41 - 5(2) = 41 - 10 = 31
  3. Determine Difference: Determine the difference between consecutive terms.\newlineThe difference between f(2)f(2) and f(1)f(1) is 3136=531 - 36 = -5.\newlineThis indicates that each term is 55 less than the previous term.
  4. Write Recursive Formula: Write the recursive formula using the difference found in Step 33.\newlineSince each term is 55 less than the previous term, the recursive formula is:\newlinef(n)=f(n1)5f(n) = f(n-1) - 5, for n > 1
  5. Combine Initial Condition: Combine the initial condition with the recursive formula.\newlineThe complete recursive formula for the sequence is:\newline:[f(1)=36],[f(n)=f(n1)5]:{:[f(1)=36],[f(n)=f(n-1)-5]:}, for n > 1

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