Q. f(n)=41−5nComplete the recursive formula of f(n).f(1)=□f(n)=f(n−1)+□
Find First Term: Find the first term of the sequence.To find the first term, we substitute n=1 into the function f(n)=41−5n.f(1)=41−5(1)=41−5=36
Find Second Term: Find the second term of the sequence to observe the pattern.Substitute n=2 into the function f(n)=41−5n.f(2)=41−5(2)=41−10=31
Determine Difference: Determine the difference between consecutive terms.The difference between f(2) and f(1) is 31−36=−5.This indicates that each term is 5 less than the previous term.
Write Recursive Formula: Write the recursive formula using the difference found in Step 3.Since each term is 5 less than the previous term, the recursive formula is:f(n)=f(n−1)−5, for n > 1
Combine Initial Condition: Combine the initial condition with the recursive formula.The complete recursive formula for the sequence is::[f(1)=36],[f(n)=f(n−1)−5]:, for n > 1
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