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Express the following in vertex form

f(x)=x^(2)+6x-2

Express the following in vertex form\newlinef(x)=x2+6x2f(x)=x^{2}+6 x-2

Full solution

Q. Express the following in vertex form\newlinef(x)=x2+6x2f(x)=x^{2}+6 x-2
  1. Identify Coefficients: To express the quadratic function f(x)=x2+6x2f(x) = x^2 + 6x - 2 in vertex form, we need to complete the square.\newlineVertex form of a quadratic function is given by f(x)=a(xh)2+kf(x) = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.\newlineFirst, we need to identify the coefficient of x2x^2, which is 11 (a=1a = 1), and the coefficient of xx, which is 66 (b=6b = 6).
  2. Complete the Square: Next, we take half of the coefficient of xx, which is 66, and square it to complete the square.(62)2=32=9.(\frac{6}{2})^2 = 3^2 = 9.We will add and subtract this number inside the parentheses to complete the square.
  3. Rewrite the Function: Now, we rewrite the function by adding and subtracting 99 inside the parentheses: f(x)=x2+6x+992f(x) = x^2 + 6x + 9 - 9 - 2.
  4. Factor the Trinomial: We can now factor the perfect square trinomial x2+6x+9x^2 + 6x + 9 as (x+3)2(x + 3)^2:f(x)=(x+3)292.f(x) = (x + 3)^2 - 9 - 2.
  5. Combine Constants: Finally, we combine the constants to simplify the expression: f(x)=(x+3)211f(x) = (x + 3)^2 - 11.

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