Q. Express the following in vertex formf(x)=x2+6x−2
Identify Coefficients: To express the quadratic function f(x)=x2+6x−2 in vertex form, we need to complete the square.Vertex form of a quadratic function is given by f(x)=a(x−h)2+k, where (h,k) is the vertex of the parabola.First, we need to identify the coefficient of x2, which is 1 (a=1), and the coefficient of x, which is 6 (b=6).
Complete the Square: Next, we take half of the coefficient of x, which is 6, and square it to complete the square.(26)2=32=9.We will add and subtract this number inside the parentheses to complete the square.
Rewrite the Function: Now, we rewrite the function by adding and subtracting 9 inside the parentheses: f(x)=x2+6x+9−9−2.
Factor the Trinomial: We can now factor the perfect square trinomial x2+6x+9 as (x+3)2:f(x)=(x+3)2−9−2.
Combine Constants: Finally, we combine the constants to simplify the expression: f(x)=(x+3)2−11.
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