Complete the square to re-write the quadratic function in vertex form: y=x^(2)+3x+8 Answer: y=

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Complete the square to re-write the quadratic function in vertex form:  y=x^(2)+3x+8 Answer:  y=

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Focus on x^2 and x terms: To complete the square and rewrite the quadratic function in vertex form, we first need to focus on the x^2 and x terms. The vertex form of a quadratic function is y = a(x - h)^2 + k, where (h, k) is the vertex of the parabola. To complete the square, we need to create a perfect square trinomial from the x^2 and x terms.Create perfect square trinomial: The coefficient of x^2 is 1, which is already in the form we need. To create a perfect square trinomial, we take the coefficient of x, which is 3, divide it by 2, and square the result. This will give us the constant term we need to add and then subtract to complete the square. (3/2)^2 = 2.25 or 9/4Add and subtract constant term: We add and subtract (3/2)^2 inside the equation to maintain the equality. We add it to create the perfect square trinomial and subtract it to keep the equation balanced. y = x^2 + 3x + (3/2)^2 - (3/2)^2 + 8Simplify the equation: Now we simplify the equation by combining the constant terms. y = x^2 + 3x + 9/4 - 9/4 + 8 y = x^2 + 3x + 9/4 + 32/4 - 9/4 y = x^2 + 3x + 23/4Factor perfect square trinomial: Next, we factor the perfect square trinomial and combine the constant terms outside the square. y = (x + 3/2)^2 + 23/4Quadratic function in vertex form: This is the quadratic function in vertex form. The vertex form is y = a(x - h)^2 + k, so our h is -3/2 and our k is 23/4.

Complete the square to re-write the quadratic function in vertex form: $\newline$ $y=x^{2}+3 x+8$ $\newline$ Answer: $y=$

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Complete the square to re-write the quadratic function in vertex form:\newliney=x2+3x+8 y=x^{2}+3 x+8 y=x2+3x+8\newlineAnswer: y= y= y=

Complete the square to re-write the quadratic function in vertex form: $\newline$ $y=x^{2}+3 x+8$ $\newline$ Answer: $y=$