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Evaluate the summation below.

3sum_(m=0)^(4)(2m^(2)-6)
Answer:

Evaluate the summation below.\newline3m=04(2m26) 3 \sum_{m=0}^{4}\left(2 m^{2}-6\right) \newlineAnswer:

Full solution

Q. Evaluate the summation below.\newline3m=04(2m26) 3 \sum_{m=0}^{4}\left(2 m^{2}-6\right) \newlineAnswer:
  1. Understand Summation Notation: First, we need to understand the summation notation. The expression 3m=04(2m26)3\sum_{m=0}^{4} (2m^2 - 6) means that we will substitute mm with each integer from 00 to 44 into the expression (2m26)(2m^2 - 6), sum all the resulting values, and then multiply the sum by 33.
  2. Substitute m=0m=0: Let's start by substituting m=0m=0 into the expression (2m26)(2m^2 - 6). This gives us 2(0)262(0)^2 - 6, which simplifies to 060 - 6, resulting in 6-6.
  3. Substitute m=1m=1: Next, substitute m=1m=1 into the expression (2m26)(2m^2 - 6). This gives us 2(1)262(1)^2 - 6, which simplifies to 262 - 6, resulting in 4-4.
  4. Substitute m=2m=2: Now, substitute m=2m=2 into the expression (2m26)(2m^2 - 6). This gives us 2(2)262(2)^2 - 6, which simplifies to 2(4)62(4) - 6, resulting in 868 - 6, which is 22.
  5. Substitute m=3m=3: Substitute m=3m=3 into the expression (2m26)(2m^2 - 6). This gives us 2(3)262(3)^2 - 6, which simplifies to 2(9)62(9) - 6, resulting in 18618 - 6, which is 1212.
  6. Substitute m=4m=4: Finally, substitute m=4m=4 into the expression (2m26)(2m^2 - 6). This gives us 2(4)262(4)^2 - 6, which simplifies to 2(16)62(16) - 6, resulting in 32632 - 6, which is 2626.
  7. Add Substitution Results: Now, we add all the values obtained from the substitutions: 6+(4)+2+12+26-6 + (-4) + 2 + 12 + 26. This results in a sum of 3030.
  8. Multiply by 33: The last step is to multiply the sum by 33, as indicated by the expression 3Σ3\Sigma. So we calculate 3×303 \times 30, which equals 9090.

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