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Let’s check out your problem:
Evaluate the expression for
z
=
−
18
z = -18
z
=
−
18
.
\newline
15
+
z
=
15 + z =
15
+
z
=
_____
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Math Problems
Algebra 1
Evaluate variable expressions involving integers
Full solution
Q.
Evaluate the expression for
z
=
−
18
z = -18
z
=
−
18
.
\newline
15
+
z
=
15 + z =
15
+
z
=
_____
Write Expression with Substitution:
Write
15
+
z
15 + z
15
+
z
after substituting
z
=
−
18
z = -18
z
=
−
18
.
\newline
Substitute
−
18
-18
−
18
for
z
z
z
in
15
+
z
15 + z
15
+
z
.
\newline
15
+
(
−
18
)
15 + (-18)
15
+
(
−
18
)
Substitute Value for Variable:
Evaluate
15
+
(
−
18
)
15 + (-18)
15
+
(
−
18
)
.
\newline
15
+
(
−
18
)
15 + (-18)
15
+
(
−
18
)
\newline
=
15
−
18
= 15 - 18
=
15
−
18
\newline
=
−
3
= -3
=
−
3
More problems from Evaluate variable expressions involving integers
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What is the midline equation of
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9
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y
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□
\begin{array}{l} y=-9 \cos \left(\frac{\pi}{2} x-6\right)+8 ? \\ y=\square \end{array}
y
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Question
z
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z=11.1 i-45
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\newline
Re
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Question
(
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14
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Express your answer in the form
(
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+
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i
)
(a+b i)
(
a
+
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)
.
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Posted 10 months ago
Question
(
12
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32
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Express your answer in the form
(
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Posted 10 months ago
Question
What happens to the value of the expression
3
y
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y
\frac{3 y}{2 y}
2
y
3
y
as
y
y
y
increases?
\newline
Choose
1
1
1
answer:
\newline
(A) It increases.
\newline
(B) It decreases.
\newline
(C) It stays the same.
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Posted 10 months ago
Question
Find the following trigonometric values.
\newline
Express your answers exactly.
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7
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4
)
=
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sin
(
7
π
4
)
=
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cos
(
4
7
π
)
=
□
sin
(
4
7
π
)
=
□
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Posted 10 months ago
Question
Which equation has a constant of proportionality equal to
3
3
3
?
\newline
Choose
1
1
1
answer:
\newline
(A)
y
=
8
5
x
y=\frac{8}{5} x
y
=
5
8
x
\newline
(B)
y
=
1
3
x
y=\frac{1}{3} x
y
=
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x
\newline
(C)
y
=
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x
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y
=
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x
\newline
(D)
y
=
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6
x
y=\frac{18}{6} x
y
=
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18
x
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Posted 9 months ago
Question
Reduce to simplest form.
\newline
−
5
8
+
(
−
8
5
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=
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8
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8
)
=
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Posted 9 months ago
Question
Reduce to simplest form.
\newline
−
1
4
−
(
−
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5
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=
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4
1
−
(
−
5
3
)
=
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Posted 9 months ago
Question
Reduce to simplest form.
\newline
−
1
3
−
(
−
3
5
)
=
-\frac{1}{3}-\left(-\frac{3}{5}\right)=
−
3
1
−
(
−
5
3
)
=
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Posted 9 months ago
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