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Let’s check out your problem:
Evaluate the expression for
n
=
−
1
n = -1
n
=
−
1
.
\newline
−
12
n
−
16
=
-12n - 16 =
−
12
n
−
16
=
_____
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Math Problems
Algebra 1
Evaluate variable expressions involving integers
Full solution
Q.
Evaluate the expression for
n
=
−
1
n = -1
n
=
−
1
.
\newline
−
12
n
−
16
=
-12n - 16 =
−
12
n
−
16
=
_____
Substitute
n
=
−
1
n = -1
n
=
−
1
:
Substitute
n
=
−
1
n = -1
n
=
−
1
into the expression
−
12
n
−
16
-12n - 16
−
12
n
−
16
.
\newline
Substitute
−
1
-1
−
1
for
n
n
n
in
−
12
n
−
16
-12n - 16
−
12
n
−
16
to get
−
12
(
−
1
)
−
16
-12(-1) - 16
−
12
(
−
1
)
−
16
.
Evaluate expression:
Evaluate
–
12
(
–
1
)
−
16
–12(–1) − 16
–12
(
–1
)
−16
.
\newline
Multiplying
–
12
–12
–12
by
–
1
–1
–1
gives
12
12
12
, so the expression becomes
12
−
16
12 − 16
12−16
.
Subtract to get result:
Subtract
16
16
16
from
12
12
12
.
12
−
16
12 - 16
12
−
16
equals
−
4
-4
−
4
.
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2
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1
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\newline
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Which equation has a constant of proportionality equal to
3
3
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\newline
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1
1
1
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\newline
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y
=
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5
x
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Question
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\newline
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Reduce to simplest form.
\newline
−
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−
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Reduce to simplest form.
\newline
−
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−
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5
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3
1
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