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Evaluate:

sum_(n=2)^(6)(nx-3)
Answer:

Evaluate:\newlinen=26(nx3) \sum_{n=2}^{6}(n x-3) \newlineAnswer:

Full solution

Q. Evaluate:\newlinen=26(nx3) \sum_{n=2}^{6}(n x-3) \newlineAnswer:
  1. Substitute nn values: We are asked to evaluate the sum of the expression (nx3)(nx - 3) as nn varies from 22 to 66. This means we will substitute nn with each integer from 22 to 66 into the expression, calculate the value, and then sum all the results together.
  2. Calculate terms: First, substitute n=2n = 2 into the expression (nx3)(nx - 3) to get the first term of the sum.2x32x - 3
  3. Add all terms: Next, substitute n=3n = 3 into the expression (nx3)(nx - 3) to get the second term of the sum.3x33x - 3
  4. Combine like terms: Then, substitute n=4n = 4 into the expression (nx3)(nx - 3) to get the third term of the sum.4x34x - 3
  5. Simplify terms: After that, substitute n=5n = 5 into the expression (nx3)(nx - 3) to get the fourth term of the sum.5x35x - 3
  6. Calculate sum: Finally, substitute n=6n = 6 into the expression (nx3)(nx - 3) to get the fifth term of the sum.6x36x - 3
  7. Calculate sum: Finally, substitute n=6n = 6 into the expression (nx3)(nx - 3) to get the fifth term of the sum.6x36x - 3Now, add all the terms together to find the sum.(2x3)+(3x3)+(4x3)+(5x3)+(6x3)(2x - 3) + (3x - 3) + (4x - 3) + (5x - 3) + (6x - 3)
  8. Calculate sum: Finally, substitute n=6n = 6 into the expression (nx3)(nx - 3) to get the fifth term of the sum.6x36x - 3Now, add all the terms together to find the sum.(2x3)+(3x3)+(4x3)+(5x3)+(6x3)(2x - 3) + (3x - 3) + (4x - 3) + (5x - 3) + (6x - 3)Combine like terms by adding all the xx terms together and all the constant terms together.2x+3x+4x+5x+6x333332x + 3x + 4x + 5x + 6x - 3 - 3 - 3 - 3 - 3
  9. Calculate sum: Finally, substitute n=6n = 6 into the expression (nx3)(nx - 3) to get the fifth term of the sum.6x36x - 3Now, add all the terms together to find the sum.(2x3)+(3x3)+(4x3)+(5x3)+(6x3)(2x - 3) + (3x - 3) + (4x - 3) + (5x - 3) + (6x - 3)Combine like terms by adding all the xx terms together and all the constant terms together.2x+3x+4x+5x+6x333332x + 3x + 4x + 5x + 6x - 3 - 3 - 3 - 3 - 3Simplify the xx terms and the constant terms.(2x+3x+4x+5x+6x)(3+3+3+3+3)(2x + 3x + 4x + 5x + 6x) - (3 + 3 + 3 + 3 + 3)
  10. Calculate sum: Finally, substitute n=6n = 6 into the expression (nx3)(nx - 3) to get the fifth term of the sum.6x36x - 3Now, add all the terms together to find the sum.(2x3)+(3x3)+(4x3)+(5x3)+(6x3)(2x - 3) + (3x - 3) + (4x - 3) + (5x - 3) + (6x - 3)Combine like terms by adding all the xx terms together and all the constant terms together.2x+3x+4x+5x+6x333332x + 3x + 4x + 5x + 6x - 3 - 3 - 3 - 3 - 3Simplify the xx terms and the constant terms.(2x+3x+4x+5x+6x)(3+3+3+3+3)(2x + 3x + 4x + 5x + 6x) - (3 + 3 + 3 + 3 + 3)Calculate the sum of the xx terms and the sum of the constants.20x1520x - 15

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