Substitute n values: We are asked to evaluate the sum of the expression (nx−3) as n varies from 2 to 6. This means we will substitute n with each integer from 2 to 6 into the expression, calculate the value, and then sum all the results together.
Calculate terms: First, substitute n=2 into the expression (nx−3) to get the first term of the sum.2x−3
Add all terms: Next, substitute n=3 into the expression (nx−3) to get the second term of the sum.3x−3
Combine like terms: Then, substitute n=4 into the expression (nx−3) to get the third term of the sum.4x−3
Simplify terms: After that, substitute n=5 into the expression (nx−3) to get the fourth term of the sum.5x−3
Calculate sum: Finally, substitute n=6 into the expression (nx−3) to get the fifth term of the sum.6x−3
Calculate sum: Finally, substitute n=6 into the expression (nx−3) to get the fifth term of the sum.6x−3Now, add all the terms together to find the sum.(2x−3)+(3x−3)+(4x−3)+(5x−3)+(6x−3)
Calculate sum: Finally, substitute n=6 into the expression (nx−3) to get the fifth term of the sum.6x−3Now, add all the terms together to find the sum.(2x−3)+(3x−3)+(4x−3)+(5x−3)+(6x−3)Combine like terms by adding all the x terms together and all the constant terms together.2x+3x+4x+5x+6x−3−3−3−3−3
Calculate sum: Finally, substitute n=6 into the expression (nx−3) to get the fifth term of the sum.6x−3Now, add all the terms together to find the sum.(2x−3)+(3x−3)+(4x−3)+(5x−3)+(6x−3)Combine like terms by adding all the x terms together and all the constant terms together.2x+3x+4x+5x+6x−3−3−3−3−3Simplify the x terms and the constant terms.(2x+3x+4x+5x+6x)−(3+3+3+3+3)
Calculate sum: Finally, substitute n=6 into the expression (nx−3) to get the fifth term of the sum.6x−3Now, add all the terms together to find the sum.(2x−3)+(3x−3)+(4x−3)+(5x−3)+(6x−3)Combine like terms by adding all the x terms together and all the constant terms together.2x+3x+4x+5x+6x−3−3−3−3−3Simplify the x terms and the constant terms.(2x+3x+4x+5x+6x)−(3+3+3+3+3)Calculate the sum of the x terms and the sum of the constants.20x−15
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