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Evaluate:

sum_(n=0)^(2)(nx+1)
Answer:

Evaluate:\newlinen=02(nx+1) \sum_{n=0}^{2}(n x+1) \newlineAnswer:

Full solution

Q. Evaluate:\newlinen=02(nx+1) \sum_{n=0}^{2}(n x+1) \newlineAnswer:
  1. Evaluate Expression Range: We are asked to evaluate the sum of the expression nx+1n x + 1 for nn ranging from 00 to 22. This is a finite series where we substitute the values of nn into the expression and sum the results.
  2. Substitute n=0n = 0: First, substitute n=0n = 0 into the expression (nx+1)(nx + 1). This gives us (0×x+1)(0\times x + 1), which simplifies to 11.
  3. Substitute n=1n = 1: Next, substitute n=1n = 1 into the expression (nx+1)(nx + 1). This gives us (1×x+1)(1\times x + 1), which simplifies to (x+1)(x + 1).
  4. Substitute n=2n = 2: Finally, substitute n=2n = 2 into the expression (n×x+1)(n\times x + 1). This gives us (2×x+1)(2\times x + 1), which simplifies to (2x+1)(2x + 1).
  5. Sum Substitutions: Now, sum the results of the substitutions: 1+(x+1)+(2x+1)1 + (x + 1) + (2x + 1).
  6. Combine Like Terms: Combine like terms: 1+x+1+2x+1=3+3x1 + x + 1 + 2x + 1 = 3 + 3x.

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