Evaluate cube root of −3: First, we need to evaluate the cube root of −3, which is written as (−3)31. The cube root of a negative number is negative, so (−3)31=−331=−1.
Evaluate cube root of (1/375): Next, we evaluate the cube root of (1/375), which is written as (1/375)1/3. To find the cube root of a fraction, we find the cube root of the numerator and the denominator separately.
Evaluate cube root of 1: The cube root of 1 is 1, because 1 raised to any power is 1. So, (1)31=1.
Factorize and simplify cube root of 375: Now, we find the cube root of 375. We can factor 375 as 3×125, and 125 is a perfect cube (5×5×5). So, $(\(375\))^{\(1\)/\(3\)} = (\(3\)\times\(125\))^{\(1\)/\(3\)} = \(3\)^{\(1\)/\(3\)} \times \(125\)^{\(1\)/\(3\)} = \(3\)^{\(1\)/\(3\)} \times \(5\).
Take reciprocal of cube root of \((1/375)\): Since \(3^{(1/3)}\) is the cube root of \(3\), and we cannot simplify it further without a calculator, we leave it as is. So, \((375)^{(1/3)} = 3^{(1/3)} \times 5\).
Multiply cube roots of \(-3\) and \((1/375)\): Now, we take the reciprocal of \((375)^{(1/3)}\) because we are dealing with \((1/375)^{(1/3)}\). The reciprocal of \(3^{(1/3)} \times 5\) is \(1 / (3^{(1/3)} \times 5)\).
Simplify the expression: Multiplying the cube root of \(-3\) by the cube root of \(\frac{1}{375}\), we get: \((-1) \times \left(\frac{1}{3^{\frac{1}{3}} \times 5}\right) = -\frac{1}{3^{\frac{1}{3}} \times 5}\).
Simplify the expression: Multiplying the cube root of \(-3\) by the cube root of \(\frac{1}{375}\), we get: \((-1) \times \left(\frac{1}{3^{\frac{1}{3}} \times 5}\right) = -\frac{1}{3^{\frac{1}{3}} \times 5}\). Simplify the expression to get the final answer: \(-\frac{1}{3^{\frac{1}{3}} \times 5} = -\frac{1}{5 \times 3^{\frac{1}{3}}}\).
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