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Edgar had three times as many pairs of sunglasses as his friend Ted. Since Edgar didn't wear all of them regularly, he gave four pairs to Ted. Now they have the same number of pairs.\newlineWhich equation can you use to find tt, the number of pairs Ted had initially?\newlineChoices:\newline(A) 3t=t+43t = t + 4\newline(B) 3t4=t+43t - 4 = t + 4\newlineHow many pairs of sunglasses did Ted have initially?\newline____\_\_\_\_ pairs\newline

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Q. Edgar had three times as many pairs of sunglasses as his friend Ted. Since Edgar didn't wear all of them regularly, he gave four pairs to Ted. Now they have the same number of pairs.\newlineWhich equation can you use to find tt, the number of pairs Ted had initially?\newlineChoices:\newline(A) 3t=t+43t = t + 4\newline(B) 3t4=t+43t - 4 = t + 4\newlineHow many pairs of sunglasses did Ted have initially?\newline____\_\_\_\_ pairs\newline
  1. Initial Denotation of Pairs: Let's denote the number of pairs Ted had initially as tt. According to the problem, Edgar had three times as many pairs as Ted, so Edgar had 3t3t pairs. After giving four pairs to Ted, Edgar and Ted have the same number of pairs. This means that Edgar's new number of pairs (3t4)(3t - 4) is equal to Ted's new number of pairs (t+4)(t + 4). The equation representing this situation is: 3t4=t+43t - 4 = t + 4
  2. Equation Setup: To solve for tt, we need to isolate the variable on one side of the equation. We can do this by subtracting tt from both sides of the equation to get rid of the tt on the right side.\newline3t4t=t+4t3t - 4 - t = t + 4 - t\newlineThis simplifies to:\newline2t4=42t - 4 = 4
  3. Isolating the Variable: Next, we add 44 to both sides of the equation to isolate the term with tt on the left side.\newline2t4+4=4+42t - 4 + 4 = 4 + 4\newlineThis simplifies to:\newline2t=82t = 8
  4. Solving for t: Finally, we divide both sides of the equation by 22 to solve for t.\newline2t2=82\frac{2t}{2} = \frac{8}{2}\newlineThis gives us:\newlinet=4t = 4

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