Divide the polynomials. Your answer should be in the form p(x)+(k)/(x-5) where p is a polynomial and k is an integer. (x^(2)-9x+14)/(x-5)=

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Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x-5) where  p is a polynomial and  k is an integer.  (x^(2)-9x+14)/(x-5)=

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Set up division: Set up the division of the polynomials. We are dividing the polynomial x^2 - 9x + 14 by x - 5. We will use polynomial long division to find the quotient and the remainder.Divide first term: Divide the first term of the numerator by the first term of the denominator. Divide x^2 by x to get x. This will be the first term of the quotient polynomial p(x).Multiply and subtract: Multiply the divisor by the term found in Step 2 and subtract from the numerator. Multiply x by x - 5 to get x^2 - 5x. Subtract this from x^2 - 9x + 14 to find the new numerator. (x^2 - 9x + 14) - (x^2 - 5x) = -4x + 14.Repeat division process: Repeat the division process with the new numerator. Divide -4x by x to get -4. This will be the next term of the quotient polynomial p(x).Write final answer: Multiply the divisor by the term found in Step 4 and subtract from the new numerator. Multiply -4 by x - 5 to get -4x + 20. Subtract this from -4x + 14 to find the remainder. (-4x + 14) - (-4x + 20) = -6.Write the final answer. The quotient polynomial p(x) is x - 4 and the remainder is -6. The final answer is in the form p(x) + k/(x - 5), where p(x) = x - 4 and k = -6.

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x-5}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-9 x+14}{x-5}=$

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Divide the polynomials.\newlineYour answer should be in the form p(x)+kx−5 p(x)+\frac{k}{x-5} p(x)+x−5k​ where p p p is a polynomial and k k k is an integer.\newlinex2−9x+14x−5= \frac{x^{2}-9 x+14}{x-5}= x−5x2−9x+14​=

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x-5}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-9 x+14}{x-5}=$