Divide the polynomials. Your answer should be in the form p(x)+(k)/(x-2) where p is a polynomial and k is an integer. (x^(2)-3x+9)/(x-2)=

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Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x-2) where  p is a polynomial and  k is an integer.  (x^(2)-3x+9)/(x-2)=

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Set up long division: Set up the long division. We will divide the polynomial x^2 - 3x + 9 by x - 2 using long division.Divide first term: Divide the first term of the dividend by the first term of the divisor. Divide x^2 by x to get x. This will be the first term of the quotient polynomial p(x).Multiply divisor: Multiply the divisor by the term obtained in Step 2. Multiply (x - 2) by x to get x^2 - 2x.Subtract result: Subtract the result of Step 3 from the dividend. Subtract (x^2 - 2x) from x^2 - 3x + 9 to get -x + 9.Bring down next term: Bring down the next term of the dividend. Since there are no more terms to bring down, we proceed to the next step.Divide new term: Divide the new term of the dividend by the first term of the divisor. Divide -x by x to get -1. This will be the next term of the quotient polynomial p(x).Multiply divisor again: Multiply the divisor by the term obtained in Step 6. Multiply (x - 2) by -1 to get -x + 2.Subtract result again: Subtract the result of Step 7 from the new dividend. Subtract (-x + 2) from -x + 9 to get 7.Check remainder: Since the degree of the remainder (7) is less than the degree of the divisor (x - 2), we cannot continue the division. The remainder is 7, and the quotient polynomial p(x) is x - 1.Write final answer: Write the final answer in the form p(x) + (k)/(x - 2). The quotient polynomial p(x) is x - 1, and the remainder is 7, so the final answer is x - 1 + 7/(x - 2).

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x-2}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-3 x+9}{x-2}=$

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Divide the polynomials. Your answer should be in the form p(x)+kx−2 p(x)+\frac{k}{x-2} p(x)+x−2k​ where p p p is a polynomial and k k k is an integer.\newlinex2−3x+9x−2= \frac{x^{2}-3 x+9}{x-2}= x−2x2−3x+9​=

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x-2}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-3 x+9}{x-2}=$