Divide the polynomials. Your answer should be in the form p(x)+(k)/(x+5) where p is a polynomial and k is an integer. (x^(2)-28)/(x+5)=◻

Question

Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x+5) where  p is a polynomial and  k is an integer.  (x^(2)-28)/(x+5)=◻

Bytelearn · Accepted Answer

Set up division: Set up the division of the polynomials. We are dividing x^2 - 28 by x + 5. We will use polynomial long division to find the quotient.Divide first terms: Divide the first term of the numerator by the first term of the denominator. Divide x^2 by x to get x. This will be the first term of the quotient polynomial p(x).Subtract and multiply: Multiply the divisor by the term found in Step 2 and subtract from the numerator. Multiply x by x + 5 to get x^2 + 5x. Subtract this from x^2 - 28 to get -5x - 28.Divide new first term: Divide the new first term of the remainder by the first term of the divisor. Divide -5x by x to get -5. This will be the next term of the quotient polynomial p(x).Subtract and multiply: Multiply the divisor by the term found in Step 4 and subtract from the current remainder. Multiply -5 by x + 5 to get -5x - 25. Subtract this from -5x - 28 to get -3.Write final answer: Write the final answer. The quotient polynomial p(x) is x - 5, and the remainder is -3. Therefore, the final answer in the form p(x) + (k)/(x+5) is (x - 5) + (-3)/(x+5).

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x+5}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-28}{x+5}=\square$

Full solution

More problems from Powers with decimal and fractional bases

Related topics

Divide the polynomials. Your answer should be in the form p(x)+kx+5 p(x)+\frac{k}{x+5} p(x)+x+5k​ where p p p is a polynomial and k k k is an integer.\newlinex2−28x+5=□ \frac{x^{2}-28}{x+5}=\square x+5x2−28​=□

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x+5}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-28}{x+5}=\square$