Divide the polynomials. Your answer should be in the form p(x)+(k)/(x-3) where p is a polynomial and k is an integer. (x^(2)+4)/(x-3)=

Question

Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x-3) where  p is a polynomial and  k is an integer.  (x^(2)+4)/(x-3)=

Bytelearn · Accepted Answer

Set up division: Set up the division of the polynomials using long division. We are dividing x^2 + 4 by x - 3. We will use polynomial long division to find the quotient and the remainder.Divide first terms: Divide the first term of the dividend by the first term of the divisor. Divide x^2 by x to get x. This will be the first term of the quotient polynomial p(x).Subtract and find new dividend: Multiply the divisor by the term found in Step 2 and subtract from the dividend. Multiply (x - 3) by x to get x^2 - 3x. Subtract this from x^2 + 4 to find the new dividend. (x^2 + 4) - (x^2 - 3x) = 3x + 4.Divide new dividend: Divide the new dividend by the first term of the divisor. Divide 3x by x to get 3. This will be the next term of the quotient polynomial p(x).Subtract and find remainder: Multiply the divisor by the term found in Step 4 and subtract from the new dividend. Multiply (x - 3) by 3 to get 3x - 9. Subtract this from 3x + 4 to find the remainder. (3x + 4) - (3x - 9) = 13.Write final answer: Write the final answer. The quotient polynomial p(x) is x + 3 and the remainder is 13. Therefore, the final answer in the form p(x) + (k)/(x - 3) is: x + 3 + (13)/(x - 3).

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x-3}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}+4}{x-3}=$

Full solution

More problems from Negative Exponents

Related topics

Divide the polynomials.\newlineYour answer should be in the form p(x)+kx−3 p(x)+\frac{k}{x-3} p(x)+x−3k​ where p p p is a polynomial and k k k is an integer.\newlinex2+4x−3= \frac{x^{2}+4}{x-3}= x−3x2+4​=

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x-3}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}+4}{x-3}=$