Divide the polynomials. Your answer should be in the form p(x)+(k)/(x-1) where p is a polynomial and k is an integer. (x^(2)+6x-4)/(x-1)=

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Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x-1) where  p is a polynomial and  k is an integer.  (x^(2)+6x-4)/(x-1)=

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Set up long division: Set up the long division. We will use long division to divide the polynomial x^2 + 6x - 4 by x - 1.Divide first term: Divide the first term of the dividend by the first term of the divisor. Divide x^2 by x to get x. This will be the first term of the quotient.Multiply divisor and quotient: Multiply the divisor by the first term of the quotient. Multiply x - 1 by x to get x^2 - x.Subtract result: Subtract the result from the dividend. Subtract (x^2 - x) from x^2 + 6x - 4 to get 7x - 4.Bring down next term: Bring down the next term. Since there are no more terms to bring down, we proceed to the next step.Divide new term: Divide the new term by the first term of the divisor. Divide 7x by x to get 7. This will be the next term of the quotient.Multiply divisor and new term: Multiply the divisor by the new term of the quotient. Multiply x - 1 by 7 to get 7x - 7.Subtract result: Subtract the result from the new term of the dividend. Subtract (7x - 7) from 7x - 4 to get 3.Check degree of remainder: Since the degree of the remainder (0) is less than the degree of the divisor (1), we cannot continue the division. The remainder is 3, and the quotient is x + 7.Write final answer: Write the final answer in the form p(x) + (k)/(x - 1). The quotient is x + 7 and the remainder is 3, so the final answer is p(x) = x + 7 and k = 3.

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x-1}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}+6 x-4}{x-1}=$

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Divide the polynomials. Your answer should be in the form p(x)+kx−1 p(x)+\frac{k}{x-1} p(x)+x−1k​ where p p p is a polynomial and k k k is an integer.\newlinex2+6x−4x−1= \frac{x^{2}+6 x-4}{x-1}= x−1x2+6x−4​=

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x-1}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}+6 x-4}{x-1}=$