Divide the polynomials. Your answer should be in the form p(x)+(k)/(x+1) where p is a polynomial and k is an integer. (x^(2)-2x-8)/(x+1)=

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Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x+1) where  p is a polynomial and  k is an integer.  (x^(2)-2x-8)/(x+1)=

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Set up division: Set up the division of the polynomials. We are dividing the polynomial x^2 - 2x - 8 by x + 1. We will use polynomial long division to find the quotient and the remainder.Divide first term: Divide the first term of the numerator by the first term of the denominator. Divide x^2 by x to get x. This will be the first term of the quotient polynomial p(x).Multiply divisor: Multiply the divisor by the first term of the quotient. Multiply x by x + 1 to get x^2 + x. This will be subtracted from the numerator.Subtract result: Subtract the result from the numerator. Subtract (x^2 + x) from x^2 - 2x - 8 to get -3x - 8.Bring down next term: Bring down the next term of the numerator. Since there are no more terms to bring down, we proceed to the next step.Divide new term: Divide the new term of the numerator by the first term of the denominator. Divide -3x by x to get -3. This will be the next term of the quotient polynomial p(x).Multiply divisor: Multiply the divisor by the new term of the quotient. Multiply -3 by x + 1 to get -3x - 3. This will be subtracted from the current numerator.Subtract result: Subtract the result from the current numerator. Subtract (-3x - 3) from -3x - 8 to get -5. This is the remainder of the division.Write final answer: Write the final answer. The quotient polynomial p(x) is x - 3, and the remainder is -5. Therefore, the final answer in the form p(x) + (k)/(x+1) is (x - 3) + (-5)/(x+1).

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x+1}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-2 x-8}{x+1}=$

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Divide the polynomials. Your answer should be in the form p(x)+kx+1 p(x)+\frac{k}{x+1} p(x)+x+1k​ where p p p is a polynomial and k k k is an integer.\newlinex2−2x−8x+1= \frac{x^{2}-2 x-8}{x+1}= x+1x2−2x−8​=

Divide the polynomials. Your answer should be in the form $p(x)+\frac{k}{x+1}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}-2 x-8}{x+1}=$