Divide the polynomials. Your answer should be in the form p(x)+(k)/(x+3) where p is a polynomial and k is an integer. (x^(2)+5x+5)/(x+3)=

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Divide the polynomials. Your answer should be in the form  p(x)+(k)/(x+3) where  p is a polynomial and  k is an integer.  (x^(2)+5x+5)/(x+3)=

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Set up long division: Set up the long division. We will divide the polynomial x^2 + 5x + 5 by x + 3 using long division.Divide first term: Divide the first term of the dividend by the first term of the divisor. Divide x^2 by x to get x. This will be the first term of the quotient polynomial p(x).Multiply and subtract: Multiply the divisor by the term obtained in Step 2 and subtract from the dividend. Multiply x by x + 3 to get x^2 + 3x. Subtract this from x^2 + 5x + 5 to get the new dividend. (x^2 + 5x + 5) - (x^2 + 3x) = 2x + 5.Divide new dividend: Divide the new dividend by the first term of the divisor. Divide 2x by x to get 2. This will be the next term of the quotient polynomial p(x).Multiply and subtract: Multiply the divisor by the term obtained in Step 4 and subtract from the new dividend. Multiply 2 by x + 3 to get 2x + 6. Subtract this from 2x + 5 to get the new remainder. (2x + 5) - (2x + 6) = -1.Write final answer: Write the final answer. The quotient polynomial p(x) is x + 2 and the remainder is -1. Therefore, the final answer is in the form p(x) + k/(x + 3), where p(x) = x + 2 and k = -1.

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x+3}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}+5 x+5}{x+3}=$

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Divide the polynomials.\newlineYour answer should be in the form p(x)+kx+3 p(x)+\frac{k}{x+3} p(x)+x+3k​ where p p p is a polynomial and k k k is an integer.\newlinex2+5x+5x+3= \frac{x^{2}+5 x+5}{x+3}= x+3x2+5x+5​=

Divide the polynomials. $\newline$ Your answer should be in the form $p(x)+\frac{k}{x+3}$ where $p$ is a polynomial and $k$ is an integer. $\newline$ $\frac{x^{2}+5 x+5}{x+3}=$