Q. Divide the polynomials. Your answer should be in the form p(x)+x+4k where p is a polynomial and k is an integer.x+4x2+1=
Set up division: Set up the division of the polynomials in long division format.We will divide the polynomial x2+1 by x+4 using polynomial long division.
Determine divisor count: Determine how many times the divisor (x+4) goes into the first term of the dividend x2. The first term of the divisor x goes into the first term of the dividend x2 exactly x times because x×x=x2.
Multiply and subtract: Multiply the entire divisor (x+4) by the result from Step 2(x) and subtract it from the dividend (x2+1). Multiplying (x+4) by x gives us x2+4x. We subtract this from x2+1 to find the remainder. (x2+1)−(x2+4x)=−4x+1
Bring down next term: Bring down the next term of the dividend, if any, and repeat the process.Since there are no more terms to bring down, we now have a remainder of −4x+1.
Write result in form: Write the result in the form p(x)+x+4k where p(x) is the quotient and k is the remainder.The quotient from our division is x and the remainder is −4x+1. However, we need to express the remainder as a constant over the divisor (x+4). To do this, we continue the division process to find the constant term.
Determine remainder division: Determine how many times the divisor (x+4) goes into the remainder (−4x+1).The term −4x cannot be divided by x+4 to give a polynomial term, so we stop the division here. The remainder is −4x+1.
Express remainder as fraction: Express the remainder as a fraction over the divisor (x+4).The remainder is −4x+1, so we write it as (−4x+1)/(x+4).
Final answer: Since we cannot simplify the remainder further, we have our final answer.The final answer is p(x)+x+4k where p(x)=x and k=−4x+1.