Q. Determine whether the function f(x) is continuous at x=3.f(x)={7−2x2,−8−x,x≤3x>3f(x) is continuous at x=3f(x) is discontinuous at x=3
Check Function Definition: To determine if the function f(x) is continuous at x=3, we need to check three conditions:1. The function is defined at x=3.2. The limit of f(x) as x approaches 3 exists.3. The limit of f(x) as x approaches 3 is equal to the function value at x=3.
Find Left Limit: First, let's check if the function is defined at x=3. We look at the piece of the function that applies when x is less than or equal to3, which is f(x)=7−2x2. Plugging in x=3, we get f(3)=7−2(3)2=7−18=−11. So, the function is defined at x=3.
Find Right Limit: Next, we need to find the limit of f(x) as x approaches 3 from the left. This means we will use the piece of the function that applies when x is less than or equal to 3, which is f(x)=7−2x2. The limit as x approaches 3 from the left is the same as the function value at x=3, which we already calculated as −11.
Compare Limits: Now, we need to find the limit of f(x) as x approaches 3 from the right. This means we will use the piece of the function that applies when x is greater than 3, which is f(x)=−8−x. Plugging in x=3, we get the limit as x approaches 3 from the right to be −8−3=−11.
Check Continuity: Since the limit from the left and the limit from the right both exist and are equal to each other, the limit of f(x) as x approaches 3 exists and is equal to −11.
Check Continuity: Since the limit from the left and the limit from the right both exist and are equal to each other, the limit of f(x) as x approaches 3 exists and is equal to −11. Finally, we compare the limit of f(x) as x approaches 3, which is −11, to the function value at x=3, which is also −11. Since these two values are equal, the function is continuous at x=3.
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