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Determine the value of 
y, if 
x is 1.

y=(40)/(x+3)
Answer:

Determine the value of y y , if x x is 11.\newliney=40x+3 y=\frac{40}{x+3} \newlineAnswer:

Full solution

Q. Determine the value of y y , if x x is 11.\newliney=40x+3 y=\frac{40}{x+3} \newlineAnswer:
  1. Substitute xx with 11: We are given the equation y=40x+3y = \frac{40}{x+3} and we need to find the value of yy when xx is 11. First, substitute xx with 11 in the equation. y=401+3y = \frac{40}{1+3}
  2. Calculate inside the parentheses: Now, calculate the value inside the parentheses. 1+3=41 + 3 = 4 So, the equation becomes y=404y = \frac{40}{4}
  3. Divide to find y: Divide 4040 by 44 to find the value of yy.\newliney=40/4y = 40 / 4\newliney=10y = 10

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