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Let’s check out your problem:
Determine the number of real solutions for the
quadratic equation
2
x
2
−
3
x
+
1
=
0
2x^2 - 3x + 1 = 0
2
x
2
−
3
x
+
1
=
0
using the discriminant.
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Math Problems
Calculus
Find derivatives using the chain rule I
Full solution
Q.
Determine the number of real solutions for the quadratic equation
2
x
2
−
3
x
+
1
=
0
2x^2 - 3x + 1 = 0
2
x
2
−
3
x
+
1
=
0
using the discriminant.
Identify values:
Identify the values of
a
a
a
,
b
b
b
, and
c
c
c
.
\newline
Compare
a
x
2
+
b
x
+
c
=
0
ax^2 + bx + c = 0
a
x
2
+
b
x
+
c
=
0
and
2
x
2
−
3
x
+
1
=
0
2x^2 - 3x + 1 = 0
2
x
2
−
3
x
+
1
=
0
.
\newline
a
=
2
a = 2
a
=
2
\newline
b
=
−
3
b = -3
b
=
−
3
\newline
c
=
1
c = 1
c
=
1
Compare equations:
Substitute
a
=
2
a = 2
a
=
2
,
b
=
−
3
b = -3
b
=
−
3
, and
c
=
1
c = 1
c
=
1
into the discriminant formula
D
=
b
2
−
4
a
c
D = b^2 - 4ac
D
=
b
2
−
4
a
c
.
\newline
D
=
(
−
3
)
2
−
4
⋅
2
⋅
1
D = (-3)^2 - 4 \cdot 2 \cdot 1
D
=
(
−
3
)
2
−
4
⋅
2
⋅
1
Substitute into formula:
Simplify the discriminant.
\newline
D
=
9
−
8
D = 9 - 8
D
=
9
−
8
Simplify discriminant:
Calculate the final value of the discriminant.
\newline
D
=
1
D = 1
D
=
1
Calculate final value:
Determine the number of real solutions based on the discriminant.
\newline
Since D > 0, there are
2
2
2
real solutions.
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