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Decompose the function 
f(g(x))=(6x)^(8) into 
f(x) and 
g(x).

g(x)=

f(x)=

Decompose the function f(g(x))=(6x)8 f(g(x))=(6 x)^{8} into f(x) f(x) and g(x) g(x) .\newlineg(x)= g(x)= \newlinef(x)= f(x)=

Full solution

Q. Decompose the function f(g(x))=(6x)8 f(g(x))=(6 x)^{8} into f(x) f(x) and g(x) g(x) .\newlineg(x)= g(x)= \newlinef(x)= f(x)=
  1. Identify Inner Function: To decompose the function f(g(x))=(6x)8f(g(x))=(6x)^{8} into f(x)f(x) and g(x)g(x), we need to identify a function g(x)g(x) that when input into another function f(x)f(x) will result in the given expression (6x)8(6x)^{8}.
  2. Choose g(x)g(x) as 6x6x: Let's choose g(x)g(x) to be the inner function that represents the part inside the parentheses before the exponentiation. A natural choice for g(x)g(x) would be 6x6x, since it is the base of the exponent in the given expression.
  3. Determine f(x)f(x) as x8x^8: Now we need to determine f(x)f(x) such that when g(x)g(x) is input into f(x)f(x), the result is (6x)8(6x)^{8}. Since g(x)g(x) is 6x6x, we want f(x)f(x) to be a function that raises its input to the 88th power. Therefore, f(x)f(x) should be x8x^811.
  4. Verify Decomposition: To verify our decomposition, we can substitute g(x)g(x) into f(x)f(x) and check if we get the original function f(g(x))=(6x)8f(g(x))=(6x)^{8}. Substituting g(x)g(x) into f(x)f(x), we get f(g(x))=f(6x)=(6x)8f(g(x)) = f(6x) = (6x)^{8}, which matches the original function.

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