D=[[2],[3],[4]]" and "A=[[-2,-2]] Let H=DA. Find H. H=

Define Matrices D and A: Define the matrices D and A. Matrix D is a 3x1 matrix and matrix A is a 1x2 matrix. The matrices are given as: D = [[2], [3], [4]] A = [[-2, -2]]Check Matrix Multiplication: Determine if matrix multiplication is possible. Matrix multiplication is possible if the number of columns in the first matrix is equal to the number of rows in the second matrix. Since D is a 3x1 matrix and A is a 1x2 matrix, the multiplication is possible.Perform Matrix Multiplication: Perform the matrix multiplication. To multiply D by A, we take each element of D and multiply it by each element of A, since A only has one row. The resulting matrix H will be a 3x2 matrix. H = [[2 * -2, 2 * -2], [3 * -2, 3 * -2], [4 * -2, 4 * -2]]Calculate Resulting Matrix H: Calculate the entries of the resulting matrix H. H = [[-4, -4], [-6, -6], [-8, -8]]

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D=[[2],[3],[4]]" and "A=[[-2,-2]]
Let
H=DA. Find
H.

H=

$\mathrm{D}=\left[\begin{array}{l} 2 \\ 3 \\ 4 \end{array}\right] \text { and } \mathrm{A}=\left[\begin{array}{ll} -2 & -2 \end{array}\right]$ $\newline$ Let $\mathrm{H}=\mathrm{DA}$ . Find $\mathrm{H}$ . $\newline$ $\mathbf{H}=$

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Algebra 2

Composition of linear and quadratic functions: find a value

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\mathrm{D}=\left[\begin{array}{l} 2 \\ 3 \\ 4 \end{array}\right] \text { and } \mathrm{A}=\left[\begin{array}{ll} -2 & -2 \end{array}\right]

\newline

Let

\mathrm{H}=\mathrm{DA}

. Find

\mathrm{H}

\newline

\mathbf{H}=

Define Matrices D and A: Define the matrices D and A. $\newline$ Matrix D is a $3 \times 1$ matrix and matrix A is a $1 \times 2$ matrix. The matrices are given as: $\newline$ $D = \left[\begin{array}{c} 2 \ 3 \ 4 \end{array}\right]$ $\newline$ $A = \left[\begin{array}{cc} -2 & -2 \end{array}\right]$
Check Matrix Multiplication: Determine if matrix multiplication is possible. $\newline$ Matrix multiplication is possible if the number of columns in the first matrix is equal to the number of rows in the second matrix. Since $D$ is a $3 \times 1$ matrix and $A$ is a $1 \times 2$ matrix, the multiplication is possible.
Perform Matrix Multiplication: Perform the matrix multiplication. $\newline$ To multiply $D$ by $A$ , we take each element of $D$ and multiply it by each element of $A$ , since $A$ only has one row. The resulting matrix $H$ will be a $3 \times 2$ matrix. $\newline$ H = [[2 \times -2, 2 \times -2],$\newline [3 \times -2, 3 \times -2], $\newline$ [4 \times -2, 4 \times -2]]$
Calculate Resulting Matrix $H$ : Calculate the entries of the resulting matrix $H$ .H = \begin{bmatrix}-4 & -4\-6 & -6\-8 & -8\end{bmatrix}