Q. Complete the square to re-write the quadratic function in vertex form:y=x2−6x+8Answer: y=
Identify vertex form: Identify the vertex form of a parabola.The vertex form of a parabola is given by y=a(x−h)2+k, where (h,k) is the vertex of the parabola.
Begin with quadratic function: Begin with the given quadratic function.We have the quadratic function y=x2−6x+8.
Separate constant term: Separate the constant term from the x-terms.To complete the square, we need to isolate the x-terms. So we write the function as y=(x2−6x)+8.
Find completing square value: Find the value needed to complete the square.To complete the square for the expression x2−6x, we take half of the coefficient of x, which is −6/2=−3, and then square it, which gives us (−3)2=9.
Add/subtract value: Add and subtract the value found inside the parentheses.We add and subtract the value 9 inside the parentheses to maintain the equality: y=(x2−6x+9−9)+8.
Rewrite with perfect trinomial: Rewrite the equation with a perfect square trinomial.Now we have a perfect square trinomial inside the parentheses: y=((x−3)2−9)+8.
Simplify equation: Simplify the equation.Combine the constants outside the parentheses: y=(x−3)2−1.
More problems from Convert equations of parabolas from general to vertex form