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Chandler and his friend Alec recently bought new cell phones. Alec's phone was 20%20\% more expensive than Chandler's. Chandler also spent $37\$37 on an extended warranty and $55\$55 on a new phone case. Both friends ended up spending the same amount of money.\newlineWhich equation can you use to find pp, the price of Chandler's phone?\newlineChoices:\newline(A) 0.2p+55=p+370.2p + 55 = p + 37\newline(B) p+0.2p=p+37+55p + 0.2p = p + 37 + 55\newlineWhat was the price of Chandler's phone?\newline____ $\_\_\_\_\ \$

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Q. Chandler and his friend Alec recently bought new cell phones. Alec's phone was 20%20\% more expensive than Chandler's. Chandler also spent $37\$37 on an extended warranty and $55\$55 on a new phone case. Both friends ended up spending the same amount of money.\newlineWhich equation can you use to find pp, the price of Chandler's phone?\newlineChoices:\newline(A) 0.2p+55=p+370.2p + 55 = p + 37\newline(B) p+0.2p=p+37+55p + 0.2p = p + 37 + 55\newlineWhat was the price of Chandler's phone?\newline____ $\_\_\_\_\ \$
  1. Identify Correct Equation: Let's identify the correct equation to represent the situation.\newlineAlec's phone costs 20%20\% more than Chandler's phone. If pp represents the price of Chandler's phone, then Alec's phone costs p+0.2pp + 0.2p. Chandler also spent an additional $37\$37 on an extended warranty and $55\$55 on a phone case, making his total spending p+37+55p + 37 + 55. Since both friends spent the same amount, we can set the expressions for their spending equal to each other to find pp.
  2. Choose Correct Equation: Now, let's choose the correct equation from the given choices that matches our representation.\newlineThe correct equation is (B) p+0.2p=p+37+55p + 0.2p = p + 37 + 55, because it accounts for the 20%20\% additional cost of Alec's phone and the extra costs Chandler incurred.
  3. Simplify Equation: Simplify the equation to solve for pp. First, combine like terms on the left side: p+0.2pp + 0.2p becomes 1.2p1.2p. On the right side, add 3737 and 5555 to get 9292. So the equation simplifies to 1.2p=p+921.2p = p + 92.
  4. Isolate Terms with p: Subtract pp from both sides to isolate the terms with pp on one side.\newline1.2pp=p+92p1.2p - p = p + 92 - p\newlineThis simplifies to 0.2p=920.2p = 92.
  5. Divide to Solve for pp: Divide both sides by 0.20.2 to solve for pp.p=920.2p = \frac{92}{0.2}p=460p = 460

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