Chandler and his friend Alec recently bought new cell phones. Alec's phone was 20% more expensive than Chandler's. Chandler also spent $37 on an extended warranty and $55 on a new phone case. Both friends ended up spending the same amount of money.Which equation can you use to find p, the price of Chandler's phone?Choices:(A) p+0.2p=p+37+55(B) 0.2p+55=p+37What was the price of Chandler's phone?____$
Q. Chandler and his friend Alec recently bought new cell phones. Alec's phone was 20% more expensive than Chandler's. Chandler also spent $37 on an extended warranty and $55 on a new phone case. Both friends ended up spending the same amount of money.Which equation can you use to find p, the price of Chandler's phone?Choices:(A) p+0.2p=p+37+55(B) 0.2p+55=p+37What was the price of Chandler's phone?____$
Denote Price of Chandler's Phone: Let's denote the price of Chandler's phone as p. According to the problem, Alec's phone was 20% more expensive than Chandler's. This means Alec's phone cost p+0.2p.
Calculate Alec's Phone Cost: Chandler also spent an additional $37 on an extended warranty and $55 on a new phone case. So, Chandler's total spending is p+37+55.
Calculate Chandler's Total Spending: Since both friends ended up spending the same amount of money, we can set the total spending of Chandler equal to the cost of Alec's phone. This gives us the equation:p+0.2p=p+37+55
Set Up Equation: Now, we simplify the equation by combining like terms and constants: 1.2p=p+92
Simplify Equation: Subtract p from both sides to isolate the terms with p on one side:1.2p−p=920.2p=92
Isolate Terms with p: Now, divide both sides by 0.2 to solve for p:p=0.292p=460
More problems from Solve linear equations with variables on both sides: word problems