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What is the value of the expression below when 
y=2 ?

9y^(2)+6y-5

What is the value of the expression below when y=2y=2 ?\newline9y2+6y59y^{2}+6y-5

Full solution

Q. What is the value of the expression below when y=2y=2 ?\newline9y2+6y59y^{2}+6y-5
  1. Substitute yy with 22: First, substitute yy with 22 in the expression.9(2)2+6(2)59(2)^2 + 6(2) - 5
  2. Calculate square of 22: Now, calculate the square of 22.\newline(2)2=4(2)^2 = 4
  3. Multiply 99 by result: Next, multiply 99 by the result of (2)2(2)^2.\newline9×4=369 \times 4 = 36
  4. Multiply 66 by 22: Then, multiply 66 by 22. \newline6×2=126 \times 2 = 12
  5. Add results and subtract 55: Finally, add the results of the multiplications and subtract 55. 36+125=4336 + 12 - 5 = 43

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