Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Camilla drew a scale drawing of a house and its lot. In real life, the back patio is $27$ meters long. It is $3$ millimeters long in the drawing. What scale did Camilla use? $\newline$ $1$ millimeter : $\_\_\_$ meters

View step-by-step help

View step-by-step help

Scale drawings: word problems

Full solution

Q. Camilla drew a scale drawing of a house and its lot. In real life, the back patio is

27

meters long. It is

3

millimeters long in the drawing. What scale did Camilla use?

\newline

1

millimeter :

\_\_\_

meters

Given lengths: We have: $\newline$ Length of the back patio in real life = $27$ meters $\newline$ Length of the back patio in the drawing = $3$ millimeters $\newline$ To find the scale, we need to set up a ratio of the drawing length to the real-life length. $\newline$ Ratio = (Length of the back patio in drawing) / (Length of the back patio in real life) $\newline$ Ratio = $\frac{3 \, \text{mm}}{27 \, \text{m}}$
Calculate ratio: Now, we need to simplify the ratio. Since we want the scale in terms of $1$ millimeter to meters, we divide both the numerator and the denominator by $3$ . $\newline$ $(3 \, \text{mm} / 27 \, \text{m}) = (1 \, \text{mm} / 9 \, \text{m})$
Simplify ratio: The scale of the drawing is therefore $1$ millimeter to $9$ meters. $\newline$ Scale: $1$ mm : $9$ m

More problems from Scale drawings: word problems

Question

\newline

500

=

Posted 10 months ago

Question

\newline

2,000

=

Posted 10 months ago

Question

\newline

750

=

Posted 10 months ago

Question

\newline

1,500

=

Posted 9 months ago

Question

\newline

1,500

=

Posted 10 months ago

Question

According to Newton's Second Law of Motion, the sum of the forces that act on an object with a mass

m

that moves with an acceleration

a

m \cdot a

. An object whose mass is

80

grams has an acceleration of

20

meters per seconds squared. What calculation will give us the sum of the forces that act on the object, in Newtons (which are

\frac{\text{kg} \cdot \text{m}}{\text{s}^2}

\newline

1

\newline

80 \cdot 20

\newline

80 \cdot 1000 \cdot 20

\newline

\frac{80}{1000} \cdot 20

\newline

\frac{80}{60^2} \cdot 20

Posted 8 months ago

Question

Roselyn is driving to visit her family, who live

150

kilometers away. Her average speed is

60

kilometers per hour. The car's tank has

20

liters of fuel at the beginning of the drive, and its fuel efficiency is

6

kilometers per liter. Fuel costs

0.60

dollars per liter.

\newline

How long can Roselyn drive before she runs out of fuel?

\newline

Posted 10 months ago

Question

Astrid is in charge of building a new fleet of ships. Each ship requires

40

tons of wood, and accommodates

300

sailors. She receives a delivery of

4

tons of wood each day. The deliveries can continue for

100

days at most, afterwards the weather is too bad to allow them. Overall, she wants to build enough ships to accommodate at least

2100

\newline

How much wood does Astrid need to accommodate

2100

\newline

Posted 10 months ago

Question

Lily's car has a fuel efficiency of

8 \text{ liters}

100 \text{ kilometers}

\newline

What is the fuel efficiency of Lily's car in

\text{kilometers}

\text{liter}

\newline

\frac{\text{km}}{\text{L}}

Posted 10 months ago

Question

A sound wave travels through iron at a rate of

\frac{5120\,\text{m}}{\text{s}}

\newline

At what rate does the sound wave travel in

\frac{\text{km}}{\text{h}}

\newline

\square

\frac{\text{km}}{\text{h}}

Posted 8 months ago

Related topics

Algebra - Order of Operations Algebra - Distributive Property `X` and `Y` Axes Geometry - Scalene Triangle Common Multiple Geometry - Quadrant