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Beth and Jamal both purchased a new NebulaNote10001000 tablet. Jamal bought his tablet at full price for 410.50410.50 $\$, while Beth found a discount code that reduced the price of the tablet to 390.55390.55 $\$. Beth and Jamal both bought extra chargers at full price. Jamal could afford 11 extra charger, while Beth could afford 22 of them. In the end, both friends spent the same amount of money.\newlineWhich equation can you use to find cc, the cost of an extra charger?\newlineChoices:\newline(A) 410.50+c=390.55+2c410.50 + c = 390.55 + 2c\newline(B) 410.50c+1=390.55c+2410.50c + 1 = 390.55c + 2\newlineHow much does an extra charger cost?\newline___ $\$

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Q. Beth and Jamal both purchased a new NebulaNote10001000 tablet. Jamal bought his tablet at full price for 410.50410.50 $\$, while Beth found a discount code that reduced the price of the tablet to 390.55390.55 $\$. Beth and Jamal both bought extra chargers at full price. Jamal could afford 11 extra charger, while Beth could afford 22 of them. In the end, both friends spent the same amount of money.\newlineWhich equation can you use to find cc, the cost of an extra charger?\newlineChoices:\newline(A) 410.50+c=390.55+2c410.50 + c = 390.55 + 2c\newline(B) 410.50c+1=390.55c+2410.50c + 1 = 390.55c + 2\newlineHow much does an extra charger cost?\newline___ $\$
  1. Set up equation: Set up the equation based on the information given.\newlineBeth and Jamal spent the same amount of money. Jamal bought the tablet at full price and one extra charger, while Beth bought the tablet at a discounted price and two extra chargers. Let cc represent the cost of an extra charger.\newlineJamal's total cost: 410.50+c410.50 + c\newlineBeth's total cost: 390.55+2c390.55 + 2c\newlineSince both spent the same amount, we can set these two expressions equal to each other to find the cost of an extra charger.\newline410.50+c=390.55+2c410.50 + c = 390.55 + 2c
  2. Solve equation: Solve the equation for cc.\newlineSubtract cc from both sides to get the cc terms on one side:\newline410.50+cc=390.55+2cc410.50 + c - c = 390.55 + 2c - c\newline410.50=390.55+c410.50 = 390.55 + c\newlineNow, subtract 390.55390.55 from both sides to isolate cc:\newline410.50390.55=390.55+c390.55410.50 - 390.55 = 390.55 + c - 390.55\newline19.95=c19.95 = c
  3. Verify solution: Verify the solution.\newlinePlug the value of cc back into the original equation to ensure it satisfies the condition that both friends spent the same amount of money.\newline410.50+19.95=390.55+2(19.95)410.50 + 19.95 = 390.55 + 2(19.95)\newline430.45=390.55+39.90430.45 = 390.55 + 39.90\newline430.45=430.45430.45 = 430.45\newlineSince both sides are equal, the solution c=19.95c = 19.95 is correct.

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