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Beth and her cousin Albert both collect stamps. Beth currently has 8080 stamps in her collection, and she adds 44 more each month. Right now, Albert only has 2020 stamps in his collection, but he adds 1010 more each month.\newlineWhich equation can you use to find mm, the number of months it will take for Albert to have as many stamps as Beth?\newlineChoices:\newline(A) 804m=20+10m80 - 4m = 20 + 10m\newline(B) 80+4m=20+10m80 + 4m = 20 + 10m\newlineHow many months will it take for Albert to have as many stamps as Beth?\newline____ months\newline

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Q. Beth and her cousin Albert both collect stamps. Beth currently has 8080 stamps in her collection, and she adds 44 more each month. Right now, Albert only has 2020 stamps in his collection, but he adds 1010 more each month.\newlineWhich equation can you use to find mm, the number of months it will take for Albert to have as many stamps as Beth?\newlineChoices:\newline(A) 804m=20+10m80 - 4m = 20 + 10m\newline(B) 80+4m=20+10m80 + 4m = 20 + 10m\newlineHow many months will it take for Albert to have as many stamps as Beth?\newline____ months\newline
  1. Define Stamps After Months: Let's define the number of stamps Beth and Albert will have after mm months. Beth starts with 8080 stamps and adds 44 each month, so after mm months she will have 80+4m80 + 4m stamps. Albert starts with 2020 stamps and adds 1010 each month, so after mm months he will have 20+10m20 + 10m stamps. We want to find the value of mm when Beth and Albert have the same number of stamps.
  2. Set Equal Expressions: To find when they will have the same number of stamps, we set the expressions for the number of stamps they will have after mm months equal to each other. This gives us the equation 80+4m=20+10m80 + 4m = 20 + 10m.
  3. Subtract to Simplify: Now we need to solve for mm. First, we can subtract 4m4m from both sides to get all the mm terms on one side of the equation. This gives us 80=20+6m80 = 20 + 6m.
  4. Isolate Term with mm: Next, we subtract 2020 from both sides to isolate the term with mm. This gives us 60=6m60 = 6m.
  5. Solve for m: Finally, we divide both sides by 66 to solve for mm. This gives us m=606m = \frac{60}{6}.
  6. Final Result: Calculating 60/660 / 6, we find that m=10m = 10. So it will take Albert 1010 months to have as many stamps as Beth.

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