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Ben starts walking along a path at 
3mi//h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 
6mi//h. How long (in hours) will it be before Amanda catches up to Ben?
Enter the exact answer.
Hint: The distance formula is that distance 
= rate 
** time, so for example in one and a half hours, Ben has walked 
3**1.5 miles.
Amanda catches up to Ben in 
◻ hours.

Ben starts walking along a path at 3mi/h3\,\text{mi/h}. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 6mi/h6\,\text{mi/h}. How long (in hours) will it be before Amanda catches up to Ben? Enter the exact answer. Hint: The distance formula is that distance == rate ×\times time, so for example in one and a half hours, Ben has walked 3×1.53\times1.5 miles. Amanda catches up to Ben in \square hours.

Full solution

Q. Ben starts walking along a path at 3mi/h3\,\text{mi/h}. One and a half hours after Ben leaves, his sister Amanda begins jogging along the same path at 6mi/h6\,\text{mi/h}. How long (in hours) will it be before Amanda catches up to Ben? Enter the exact answer. Hint: The distance formula is that distance == rate ×\times time, so for example in one and a half hours, Ben has walked 3×1.53\times1.5 miles. Amanda catches up to Ben in \square hours.
  1. Calculate Distance Traveled: Calculate the distance Ben has traveled by the time Amanda starts.\newlineBen's speed = 3mi/h3 \, \text{mi/h}, Time before Amanda starts = 1.5h1.5 \, \text{h}.\newlineDistance = Speed ×\times Time = 3mi/h×1.5h=4.5mi3 \, \text{mi/h} \times 1.5 \, \text{h} = 4.5 \, \text{mi}.
  2. Set Up Equation: Set up the equation to find when Amanda catches up to Ben.\newlineLet tt be the time in hours Amanda jogs to catch up to Ben.\newlineAmanda's speed = 66 mi/h, Ben's speed = 33 mi/h.\newlineDistance Amanda covers = 6t6t mi, Distance Ben covers = 4.54.5 mi + 3t3t mi.\newlineSet distances equal to find tt: 6t=4.5+3t6t = 4.5 + 3t.
  3. Solve for t: Solve for t.\newline6t=4.5+3t6t = 4.5 + 3t\newline6t3t=4.56t - 3t = 4.5\newline3t=4.53t = 4.5\newlinet=4.53t = \frac{4.5}{3}\newlinet=1.5t = 1.5 hours.

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