Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

As president of the student council, Meg is choosing between two options for class T-shirts. A local shop charges $11\$11 for each shirt, plus a set-up fee of $100\$100. An online store charges $15\$15 for each shirt, plus a set-up fee of $24\$24.\newlineWhich equation can you use to find ss, the number of shirts Meg would need to order for the two options to cost the same?\newlineChoices:\newline(A) 11+100s=15+24s11 + 100s = 15 + 24s\newline(B) 11s+100=15s+2411s + 100 = 15s + 24\newlineHow many shirts would Meg need to order for the two options to cost the same?\newline____\_\_\_\_ shirts\newline

Full solution

Q. As president of the student council, Meg is choosing between two options for class T-shirts. A local shop charges $11\$11 for each shirt, plus a set-up fee of $100\$100. An online store charges $15\$15 for each shirt, plus a set-up fee of $24\$24.\newlineWhich equation can you use to find ss, the number of shirts Meg would need to order for the two options to cost the same?\newlineChoices:\newline(A) 11+100s=15+24s11 + 100s = 15 + 24s\newline(B) 11s+100=15s+2411s + 100 = 15s + 24\newlineHow many shirts would Meg need to order for the two options to cost the same?\newline____\_\_\_\_ shirts\newline
  1. Set Up Equations: Let's set up the equations for the total cost of the shirts for each option. For the local shop, the total cost CC is the number of shirts ss times the price per shirt plus the set-up fee: C=11s+100C = 11s + 100. For the online store, the total cost CC is also the number of shirts ss times the price per shirt plus the set-up fee: C=15s+24C = 15s + 24. To find the number of shirts ss that makes the costs equal, we set the two expressions for CC equal to each other.
  2. Write Equation: Now we write the equation that equates the two costs: 11s+100=15s+2411s + 100 = 15s + 24. This is the equation we can use to solve for ss, the number of shirts needed for the costs to be the same.
  3. Solve for s: To solve for s, we need to get all the terms with ss on one side and the constants on the other side. We can do this by subtracting 11s11s from both sides of the equation: 11s+10011s=15s+2411s11s + 100 - 11s = 15s + 24 - 11s.
  4. Isolate Term: Simplifying both sides of the equation gives us: 100=4s+24100 = 4s + 24.
  5. Subtract Constants: Next, we subtract 2424 from both sides to isolate the term with ss: 10024=4s+2424100 - 24 = 4s + 24 - 24.
  6. Divide by 44: This simplifies to 76=4s76 = 4s.
  7. Divide by 44: This simplifies to 76=4s76 = 4s.Finally, we divide both sides by 44 to solve for ss: 76/4=4s/476 / 4 = 4s / 4.
  8. Divide by 44: This simplifies to 76=4s76 = 4s. Finally, we divide both sides by 44 to solve for ss: 76/4=4s/476 / 4 = 4s / 4. This gives us s=19s = 19. So, Meg would need to order 1919 shirts for the two options to cost the same.

More problems from Solve linear equations with variables on both sides: word problems