An open-topped glass aquarium with a square base is designed to hold 32 cubic feet of water. What is the minimum possible exterior surface area of the aquarium?square feet
Q. An open-topped glass aquarium with a square base is designed to hold 32 cubic feet of water. What is the minimum possible exterior surface area of the aquarium?square feet
Define Variables: Let s be the side length of the square base and h be the height of the aquarium.Volume of the aquarium V=s2×h.
Given Volume: Given volume V=32 cubic feet.Substitute 32 for V in V=s2⋅h.32=s2⋅h.
Substitute Volume: Since the base is square and we want the minimum surface area, the aquarium will be a cube (where all sides are equal).So, s=h.
Base is a Cube: Substitute s for h in 32=s2⋅h. 32=s2⋅s. 32=s3.
Calculate Side Length: Solve for s.s=332.s=2×32.
Calculate Surface Area: Calculate the exterior surface area of the aquarium without the open top.Surface area A=4×s2+s2 (4 sides plus the base).
Calculate Surface Area: Calculate the exterior surface area of the aquarium without the open top.Surface area A=4×s2+s2 (4 sides plus the base).Substitute 2×cube root of 2 for s in A=4×s2+s2.A=4×(2×cube root of 2)2+(2×cube root of 2)2.A=4×4×2+4×2.A=32+8.A=40 square feet.
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