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An arithmetic sequence 
j starts 
22,15,dots. Explain how you would calculate the value of the 500th term.

An arithmetic sequence j j starts 22,15, 22,15, \ldots . Explain how you would calculate the value of the 500500th term.

Full solution

Q. An arithmetic sequence j j starts 22,15, 22,15, \ldots . Explain how you would calculate the value of the 500500th term.
  1. Find First Term: First term (a)=22(a) = 22 Common difference (d)=1522=7(d) = 15 - 22 = -7
  2. Arithmetic Sequence Formula: Formula for the nth term of an arithmetic sequence: an=a+(n1)d a_n = a + (n-1)d
  3. Substitute Values: Substitute n = 500500, a = 2222, and d = 7-7 into the formula:\newlinea500=22+(5001)(7) a_{500} = 22 + (500-1)(-7)
  4. Calculate n1-1: Calculate 5001 500-1 :\newline499 499
  5. Multiply by 7-7: Multiply 499499 by 7-7:\newline499×7=3493 499 \times -7 = -3493
  6. Add to Find Term: Add 2222 to 3493-3493:\newline22+(3493)=3471 22 + (-3493) = -3471

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