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Let’s check out your problem:
An arithmetic sequence
j
j
j
starts
22
,
15
,
…
22,15, \ldots
22
,
15
,
…
. Explain how you would calculate the value of the
500
500
500
th term.
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Math Problems
Grade 7
Convert between customary and metric systems
Full solution
Q.
An arithmetic sequence
j
j
j
starts
22
,
15
,
…
22,15, \ldots
22
,
15
,
…
. Explain how you would calculate the value of the
500
500
500
th term.
Find First Term:
First term
(
a
)
=
22
(a) = 22
(
a
)
=
22
Common difference
(
d
)
=
15
−
22
=
−
7
(d) = 15 - 22 = -7
(
d
)
=
15
−
22
=
−
7
Arithmetic Sequence Formula:
Formula for the nth term of an arithmetic sequence:
a
n
=
a
+
(
n
−
1
)
d
a_n = a + (n-1)d
a
n
=
a
+
(
n
−
1
)
d
Substitute Values:
Substitute n =
500
500
500
, a =
22
22
22
, and d =
−
7
-7
−
7
into the formula:
\newline
a
500
=
22
+
(
500
−
1
)
(
−
7
)
a_{500} = 22 + (500-1)(-7)
a
500
=
22
+
(
500
−
1
)
(
−
7
)
Calculate n
−
1
-1
−
1
:
Calculate
500
−
1
500-1
500
−
1
:
\newline
499
499
499
Multiply by
−
7
-7
−
7
:
Multiply
499
499
499
by
−
7
-7
−
7
:
\newline
499
×
−
7
=
−
3493
499 \times -7 = -3493
499
×
−
7
=
−
3493
Add to Find Term:
Add
22
22
22
to
−
3493
-3493
−
3493
:
\newline
22
+
(
−
3493
)
=
−
3471
22 + (-3493) = -3471
22
+
(
−
3493
)
=
−
3471
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