Alex learned 80 new vocabulary words for his English exam. The following function gives the number of words he remembers after t days:W(t)=80(1−0.1t)3What is the instantaneous rate of change of the number of words Alex remembers after 5 days?Choose 1 answer:(A) 10 days(B) 10 words per day(C) −6 days(D) −6 words per day
Q. Alex learned 80 new vocabulary words for his English exam. The following function gives the number of words he remembers after t days:W(t)=80(1−0.1t)3What is the instantaneous rate of change of the number of words Alex remembers after 5 days?Choose 1 answer:(A) 10 days(B) 10 words per day(C) −6 days(D) −6 words per day
Take Derivative of W(t): To find the instantaneous rate of change, we need to take the derivative of W(t) with respect to t.
Apply Chain Rule: Differentiate W(t)=80(1−0.1t)3. Using the chain rule, dtd[80(1−0.1t)3]=80×3×(1−0.1t)2×(−0.1).
Simplify Derivative: Simplify the derivative to get W′(t)=−24×(1−0.1t)2.
Substitute t=5: Substitute t=5 into W′(t) to find the instantaneous rate of change after 5 days.W′(5)=−24×(1−0.1×5)2.