Let f be the function defined by f(a)=∫01(2z2−15z2)dt. On which of the following intervals is the graph of y=f(x) concave down?(A) (−∞,0) only(B) (→∞,2)(C) (0,∞)(D) (2,3) only(E) (3,∞) only
Q. Let f be the function defined by f(a)=∫01(2z2−15z2)dt. On which of the following intervals is the graph of y=f(x) concave down?(A) (−∞,0) only(B) (→∞,2)(C) (0,∞)(D) (2,3) only(E) (3,∞) only
Identify Function: Identify the function inside the integral.Reasoning: The function given inside the integral is 2z2−15z+2.Calculation: No calculation needed here.
Calculate Integral: Calculate the integral of the function from 0 to 1.Reasoning: To find f(x), we need to integrate the quadratic function.Calculation: ∫01(2z2−15z+2)dz=[32z3−215z2+2z]01=(32−215+2)−(0)=32−7.5+2=−2.83.
Determine Second Derivative: Determine the second derivative of the function.Reasoning: Concavity is determined by the second derivative of the function.Calculation: Since f(x) is a constant (as the integral of a function over a fixed interval results in a constant), f′′(x)=0.
Analyze Concavity: Analyze the second derivative to find concavity.Reasoning: A function is concave down where its second derivative is less than 0.Calculation: Since f′′(x)=0 everywhere, there are no intervals where the function is concave down.
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