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A triangle has an area of 52square inches52\,\text{square inches} and a height of 8inches8\,\text{inches}. Which equation can you use to find the length of the triangle's base, bb?\newlineChoices:\newline(A) 52=12b(8+8)52 = \frac{1}{2}b(8 + 8)\newline(B) 52=12b(8)52 = \frac{1}{2}b(8)\newlineWhat is the length of the triangle's base?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ inches

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Q. A triangle has an area of 52square inches52\,\text{square inches} and a height of 8inches8\,\text{inches}. Which equation can you use to find the length of the triangle's base, bb?\newlineChoices:\newline(A) 52=12b(8+8)52 = \frac{1}{2}b(8 + 8)\newline(B) 52=12b(8)52 = \frac{1}{2}b(8)\newlineWhat is the length of the triangle's base?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ inches
  1. Identify Formula: First, let's identify the correct formula to use for calculating the base of the triangle. The area of a triangle is given by the formula Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}. We know the area (5252 square inches) and the height (88 inches), so we need to find the base, bb.
  2. Evaluate Choices: Looking at the choices, (A) 52=12b(8+8)52 = \frac{1}{2}b(8 + 8) and (B) 52=12b(8)52 = \frac{1}{2}b(8). The correct formula for the area of a triangle is Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}, which matches choice (B) because it simplifies to 52=12×b×852 = \frac{1}{2} \times b \times 8. Choice (A) incorrectly adds the height twice.
  3. Solve for Base: Now, using the correct formula from choice (B), we solve for bb. Rearrange the equation 52=12×b×852 = \frac{1}{2} \times b \times 8 to find bb. First, multiply both sides by 22 to get rid of the fraction: 104=b×8104 = b \times 8.
  4. Isolate Base: Next, divide both sides by 88 to isolate bb: b=1048b = \frac{104}{8}.
  5. Calculate Base: Calculate bb: b=13b = 13.

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