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A triangle has an area of 5252 square inches and a height of 88 inches.\newlineWhich equation can you use to find the length of the triangle's base, bb?\newlineChoices:\newline(A) 52=12b(8)52 = \frac{1}{2}b(8)\newline(B) 52=12b(8+8)52 = \frac{1}{2}b(8 + 8)\newlineWhat is the length of the triangle's base?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ inches\newline

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Q. A triangle has an area of 5252 square inches and a height of 88 inches.\newlineWhich equation can you use to find the length of the triangle's base, bb?\newlineChoices:\newline(A) 52=12b(8)52 = \frac{1}{2}b(8)\newline(B) 52=12b(8+8)52 = \frac{1}{2}b(8 + 8)\newlineWhat is the length of the triangle's base?\newlineWrite your answer as a whole number or decimal. Do not round.\newline____ inches\newline
  1. Identify Formula: Step 11: Identify the correct formula to calculate the base of the triangle.\newlineThe area of a triangle is given by the formula A=12×base×heightA = \frac{1}{2} \times \text{base} \times \text{height}. We need to rearrange this formula to solve for the base, bb. Given the area (AA) is 5252 square inches and the height (hh) is 88 inches, the correct equation to use is:\newline52=12×b×852 = \frac{1}{2} \times b \times 8
  2. Solve Equation: Step 22: Solve the equation for bb. Start by multiplying both sides of the equation by 22 to eliminate the fraction: 2×52=b×82 \times 52 = b \times 8 104=b×8104 = b \times 8 Now, divide both sides by 88 to solve for bb: 104/8=b104 / 8 = b b=13b = 13

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