Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

A single processor takes 20 milliseconds ( ms ) to prepare data entries and 0.1 nms to copy the entries, where n is the number of entries. A multiprocessor takes 70ms to prepare and copy one data entry, and whenever the number of entries is doubled the amount of time to prepare and copy them increases by 5ms. Given 120ms to prepare and copy data entries, which processor type can prepare and copy more entries and how many more entries can it prepare and copy? Choose 1 answer: (A) The single processor can prepare and copy 176 more entries. (B) The single processor can prepare and copy 989 more entries. (C) The multiprocessor can prepare and copy 24 more entries. (D) The multiprocessor can prepare and copy 1,012 more entries.

A single processor takes 2020 milliseconds ( ms \mathrm{ms} ) to prepare data entries and 0.1n ms 0.1 n \mathrm{~ms} to copy the entries, where n n is the number of entries. A multiprocessor takes 70 ms 70 \mathrm{~ms} to prepare and copy one data entry, and whenever the number of entries is doubled the amount of time to prepare and copy them increases by 5 ms 5 \mathrm{~ms} . Given 120 ms 120 \mathrm{~ms} to prepare and copy data entries, which processor type can prepare and copy more entries and how many more entries can it prepare and copy?\newlineChoose 11 answer:\newline(A) The single processor can prepare and copy 176176 more entries.\newline(B) The single processor can prepare and copy 989989 more entries.\newline(C) The multiprocessor can prepare and copy 2424 more entries.\newline(D) The multiprocessor can prepare and copy 11,012012 more entries.

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 6right chevron icon
Find a value using two-variable equations: word problemsright chevron icon

Full solution

Q. A single processor takes 2020 milliseconds ( ms \mathrm{ms} ) to prepare data entries and 0.1n ms 0.1 n \mathrm{~ms} to copy the entries, where n n is the number of entries. A multiprocessor takes 70 ms 70 \mathrm{~ms} to prepare and copy one data entry, and whenever the number of entries is doubled the amount of time to prepare and copy them increases by 5 ms 5 \mathrm{~ms} . Given 120 ms 120 \mathrm{~ms} to prepare and copy data entries, which processor type can prepare and copy more entries and how many more entries can it prepare and copy?\newlineChoose 11 answer:\newline(A) The single processor can prepare and copy 176176 more entries.\newline(B) The single processor can prepare and copy 989989 more entries.\newline(C) The multiprocessor can prepare and copy 2424 more entries.\newline(D) The multiprocessor can prepare and copy 11,012012 more entries.
  1. Calculate Single Processor Entries: Determine the number of entries the single processor can prepare and copy in 120 ms120\,\text{ms}. The time taken by the single processor to prepare and copy data entries is given by the formula: Total time =Time to prepare+Time to copy=20 ms+0.1 ms×n= \text{Time to prepare} + \text{Time to copy} = 20\,\text{ms} + 0.1\,\text{ms} \times n We need to find the value of nn when the total time is 120 ms120\,\text{ms}. 120 ms=20 ms+0.1 ms×n120\,\text{ms} = 20\,\text{ms} + 0.1\,\text{ms} \times n
  2. Solve for n: Solve for n for the single processor.\newlineSubtract 20 ms20\,\text{ms} from both sides of the equation to isolate the term with nn.\newline120 ms−20 ms=0.1 ms⋅n120\,\text{ms} - 20\,\text{ms} = 0.1\,\text{ms} \cdot n\newline100 ms=0.1 ms⋅n100\,\text{ms} = 0.1\,\text{ms} \cdot n\newlineNow, divide both sides by 0.1 ms0.1\,\text{ms} to find nn.\newlinen=100 ms0.1 msn = \frac{100\,\text{ms}}{0.1\,\text{ms}}\newlinen=1000n = 1000\newlineThe single processor can prepare and copy 10001000 entries in 120 ms120\,\text{ms}.
  3. Calculate Multiprocessor Entries: Determine the number of entries the multiprocessor can prepare and copy in 120 ms120\,\text{ms}. The time taken by the multiprocessor to prepare and copy data entries is given by the formula: Total time = 70 ms+5 ms×(doublings)70\,\text{ms} + 5\,\text{ms} \times (\text{doublings}) We need to find the number of doublings that can occur within 120 ms120\,\text{ms}. Let's denote the number of doublings as dd. Then the number of entries prepared and copied is 2d2^d. 120 ms=70 ms+5 ms×d120\,\text{ms} = 70\,\text{ms} + 5\,\text{ms} \times d
  4. Solve for d: Solve for d for the multiprocessor.\newlineSubtract 70 ms70\,\text{ms} from both sides of the equation to isolate the term with dd.\newline120 ms−70 ms=5 ms×d120\,\text{ms} - 70\,\text{ms} = 5\,\text{ms} \times d\newline50 ms=5 ms×d50\,\text{ms} = 5\,\text{ms} \times d\newlineNow, divide both sides by 5 ms5\,\text{ms} to find dd.\newlined=50 ms5 msd = \frac{50\,\text{ms}}{5\,\text{ms}}\newlined=10d = 10\newlineThe multiprocessor can double the entries 1010 times in 120 ms120\,\text{ms}.
  5. Calculate Total Entries: Calculate the number of entries the multiprocessor can prepare and copy.\newlineSince the multiprocessor can double the entries 1010 times, the number of entries is 2d2^d.\newlineNumber of entries = 2102^{10}\newlineNumber of entries = 10241024\newlineThe multiprocessor can prepare and copy 10241024 entries in 120 ms120\,\text{ms}.
  6. Compare Entries: Compare the number of entries prepared and copied by both processors. The single processor can prepare and copy 10001000 entries, while the multiprocessor can prepare and copy 10241024 entries. To find out how many more entries the multiprocessor can prepare and copy, subtract the number of entries prepared and copied by the single processor from the multiprocessor's count. More entries = 1024−10001024 - 1000 More entries = 2424 The multiprocessor can prepare and copy 2424 more entries than the single processor.

More problems from Find a value using two-variable equations: word problems

Question
This equation shows how the distance traveled by a car is related to the time spent driving. d=50t+10 d = 50t + 10 . The variable t t represents the time in hours, and the variable d d represents the distance in miles. How far does the car travel in 2 2 hours?
Get tutor helpright-arrow

Posted 10 months ago

Question
The equation shows how the cost of buying pencils is related to the number of pencils purchased. \newline c=0.5p+2 c= 0.5p+2 \newlineThe variable p p represents the number of pencils, and the variable c c represents the total cost. How much does it cost to buy 10 10 pencils?
Get tutor helpright-arrow

Posted 10 months ago

Question
This equation shows how the total score in a game is related to the number of points scored per level. s=100l+250 s = 100l + 250 . The variable l l represents the levels completed, and the variable s s represents the total score. What is the total score after completing 3 3 levels?
Get tutor helpright-arrow

Posted 7 months ago

Question
The equation shows how the amount of paint needed is related to the area to be painted. p=2a+5 p = 2a + 5 . The variable a a represents the area in square meters, and the variable p p represents the amount of paint in liters. How much paint is needed for an area of 8 8 square meters?
Get tutor helpright-arrow

Posted 7 months ago

Question
This equation shows how the total bill for a meal is related to the number of people sharing the meal. \newline b=15n+35 b = 15n + 35 \newlineThe variable n n represents the number of people, and the variable b b represents the total bill. What is the total bill for a meal shared by 4 4 people?
Get tutor helpright-arrow

Posted 10 months ago

Question
Poppy the dog weighs p p pounds, and Yumi the cat weighs y y pounds. If Poppy weighs 3636 more pounds than Yumi does, which of the following equations correctly describes the relationship between their weights?\newlineChoose 11 answer:\newline(A) p+y=36 p+y=36 \newline(B) p+36=y p+36=y \newline(C) p−y=36 p-y=36 \newline(D) y−p=36 y-p=36
Get tutor helpright-arrow

Posted 7 months ago

Question
Calvin and Melvin are two of Santa's elves. The number of toys they build is given by 11c+8m 11 c+8 m , where c c is the number of candy canes Calvin eats for breakfast and m m is the number of candy canes Melvin eats for breakfast. How many toys do they build when Calvin eats 55 candy canes and Melvin eats 33 candy canes for breakfast?
Get tutor helpright-arrow

Posted 7 months ago

Question
2w+4 2 w+4 \newlineCarly is cutting a piece of paper stock based on the width of a photo. The expression above describes the length of the paper stock, in inches, for a photo that is w w inches wide. If the photo is 88.55 inches wide, what is the length of the paper stock in inches?
Get tutor helpright-arrow

Posted 7 months ago

Question
Calvin and Melvin are two of Santa's elves. The number of toys they build is given by 11c+8m 11 c+8 m where c c is the number of candy canes Calvin eats for breakfast and m m is the number of candy canes Melvin eats for breakfast.\newlineHow many toys do they build when Calvin eats 55 candy canes and Melvin eats 33 candy canes for breakfast?\newlinetoys
Get tutor helpright-arrow

Posted 8 months ago

Question
The approval rating of a certain politician is changing at a rate of r(t) r(t) percent of the population per month (where t t is the time in months).\newlineWhat does ∫03r(t)dt \int_{0}^{3} r(t) d t represent?\newlineChoose 11 answer:\newline(A) The rate of change of the approval rating of the politician when t=3 t=3 months\newline(B) The average rate of change of the approval rating during the first three months\newline(C) The change in the percent of the population who approves of the politician during the first three months\newline(D) The percent of the population who approves of the politician when t=3 t=3 months
Get tutor helpright-arrow

Posted 7 months ago

View all (71)

Related topics

Algebra - Order of OperationsAlgebra - Distributive Property`X` and `Y` AxesGeometry - Scalene TriangleCommon MultipleGeometry - Quadrant