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A scientist mixed three chemicals, RR, SS, and TT, in a glass container. The amount of RR is 33 times the amount of SS, and the amount of TT is (1)/(6)(1)/(6) the amount of SS. What is the ratio of the amount of RR to the amount of TT?\newlineE. SS11\newlineF. SS22\newlineG. SS33\newlineH. SS44

Full solution

Q. A scientist mixed three chemicals, RR, SS, and TT, in a glass container. The amount of RR is 33 times the amount of SS, and the amount of TT is (1)/(6)(1)/(6) the amount of SS. What is the ratio of the amount of RR to the amount of TT?\newlineE. SS11\newlineF. SS22\newlineG. SS33\newlineH. SS44
  1. Denote Amounts: Let's denote the amount of S as 'ss'. According to the problem, the amount of R is 33 times the amount of S, so we can write R as 3s3s. The amount of T is (1/6)(1/6) times the amount of S, so we can write T as (1/6)s(1/6)s.
  2. Express R and T: Now, we need to find the ratio of R to T. We can write this ratio as R:TR:T. Substituting the expressions for RR and TT in terms of ss, we get (3s):(16s)(3s):(\frac{1}{6}s).
  3. Find Ratio: To simplify the ratio, we can divide both parts of the ratio by ss. This gives us 3:(1/6)3:(1/6).
  4. Simplify Ratio: To further simplify, we can multiply both parts of the ratio by 66 to get rid of the fraction. This gives us (3×6):(16×6)(3\times6):(\frac{1}{6}\times6), which simplifies to 18:118:1.

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