A scientist mixed three chemicals, R, S, and T, in a glass container. The amount of R is 3 times the amount of S, and the amount of T is (1)/(6) the amount of S. What is the ratio of the amount of R to the amount of T?E. S1F. S2G. S3H. S4
Q. A scientist mixed three chemicals, R, S, and T, in a glass container. The amount of R is 3 times the amount of S, and the amount of T is (1)/(6) the amount of S. What is the ratio of the amount of R to the amount of T?E. S1F. S2G. S3H. S4
Denote Amounts: Let's denote the amount of S as 's'. According to the problem, the amount of R is 3 times the amount of S, so we can write R as 3s. The amount of T is (1/6) times the amount of S, so we can write T as (1/6)s.
Express R and T: Now, we need to find the ratio of R to T. We can write this ratio as R:T. Substituting the expressions for R and T in terms of s, we get (3s):(61s).
Find Ratio: To simplify the ratio, we can divide both parts of the ratio by s. This gives us 3:(1/6).
Simplify Ratio: To further simplify, we can multiply both parts of the ratio by 6 to get rid of the fraction. This gives us (3×6):(61×6), which simplifies to 18:1.