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A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.
The function has period 0.8 seconds, amplitude 
6cm, and midline 
H=15cm. At time 
t=0.5 seconds, the bob is at its midline, moving towards the wall.
Find the formula of the trigonometric function that models the distance 
H from the pendulum's bob to the wall after 
t seconds. Define the function using radians.

H(t)=◻_(◻)^(-×)

A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.\newlineThe function has period 00.88 seconds, amplitude 6 cm 6 \mathrm{~cm} , and midline H=15 cm H=15 \mathrm{~cm} . At time t=0.5 t=0.5 seconds, the bob is at its midline, moving towards the wall.\newlineFind the formula of the trigonometric function that models the distance H H from the pendulum's bob to the wall after t t seconds. Define the function using radians.\newlineH(t)= H(t)=\square

Full solution

Q. A pendulum is swinging next to a wall. The distance from the bob of the swinging pendulum to the wall varies in a periodic way that can be modeled by a trigonometric function.\newlineThe function has period 00.88 seconds, amplitude 6 cm 6 \mathrm{~cm} , and midline H=15 cm H=15 \mathrm{~cm} . At time t=0.5 t=0.5 seconds, the bob is at its midline, moving towards the wall.\newlineFind the formula of the trigonometric function that models the distance H H from the pendulum's bob to the wall after t t seconds. Define the function using radians.\newlineH(t)= H(t)=\square
  1. Determine trigonometric function: Determine the trigonometric function to use.\newlineSince the pendulum is at its midline at t=0.5t=0.5 seconds and moving towards the wall, we can use the cosine function, which has a value of 00 at π/2\pi/2 radians (which corresponds to 0.50.5 seconds in this context). This is because the cosine function starts at its maximum value and decreases to 00 at π/2\pi/2, which matches the description of the pendulum's motion.
  2. Calculate angular frequency: Calculate the angular frequency.\newlineThe period TT of the function is 0.80.8 seconds. The angular frequency ω\omega is related to the period by the formula ω=2π/T\omega = 2\pi/T. Let's calculate ω\omega.\newline\omega = \(2\pi / 00.88 = 22\pi / (44/55) = (22\pi \cdot 55) / 44 = (55\pi) / 22
  3. Write function with amplitude: Write the function with the amplitude and midline.\newlineThe amplitude AA is 66 cm, and the midline HH is 1515 cm. The general form of the cosine function is H(t)=Acos(ωt)+HH(t) = A \cdot \cos(\omega t) + H. Plugging in the amplitude and midline, we get:\newlineH(t)=6cos(5π2t)+15H(t) = 6 \cdot \cos\left(\frac{5\pi}{2}t\right) + 15
  4. Adjust phase shift: Adjust the phase shift.\newlineSince the pendulum is at its midline at t=0.5t=0.5 seconds, we need to introduce a phase shift to the function. The cosine function is at its midline when the argument of the cosine is π/2\pi/2. We need to find the phase shift φ\varphi such that when t=0.5t=0.5, the argument of the cosine function is π/2\pi/2.\newlineLet's set up the equation:\newline(5π/2)×0.5+φ=π/2(5\pi/2) \times 0.5 + \varphi = \pi/2\newline(5π/4)+φ=π/2(5\pi/4) + \varphi = \pi/2\newlineφ=π/25π/4\varphi = \pi/2 - 5\pi/4\newlineφ=3π/4\varphi = -3\pi/4
  5. Write final function: Write the final function.\newlineNow we include the phase shift in the function:\newlineH(t)=6cos(5π2t3π4)+15H(t) = 6 \cdot \cos\left(\frac{5\pi}{2}t - \frac{3\pi}{4}\right) + 15\newlineThis is the trigonometric function that models the distance from the pendulum's bob to the wall after tt seconds.

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