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A pendulum is swinging next to a wall.
The distance 
D(t) (in 
cm ) between the bob of the pendulum and the wall as a function of time 
t (in seconds) can be modeled by a sinusoidal expression of the form 
a*sin(b*t)+d.
At 
t=0, when the pendulum is exactly in the middle of its swing, the bob is 
5cm away from the wall. The bob reaches the closest point to the wall, which is 
3cm from the wall, 1 second later.
Find 
D(t).

t should be in radians.

D(t)=◻

A pendulum is swinging next to a wall.\newlineThe distance D(t) D(t) (in cm \mathrm{cm} ) between the bob of the pendulum and the wall as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form asin(bt)+d a \cdot \sin (b \cdot t)+d .\newlineAt t=0 t=0 , when the pendulum is exactly in the middle of its swing, the bob is 5 cm 5 \mathrm{~cm} away from the wall. The bob reaches the closest point to the wall, which is 3 cm 3 \mathrm{~cm} from the wall, 11 second later.\newlineFind D(t) D(t) .\newlinet t should be in radians.\newlineD(t)= D(t)=\square

Full solution

Q. A pendulum is swinging next to a wall.\newlineThe distance D(t) D(t) (in cm \mathrm{cm} ) between the bob of the pendulum and the wall as a function of time t t (in seconds) can be modeled by a sinusoidal expression of the form asin(bt)+d a \cdot \sin (b \cdot t)+d .\newlineAt t=0 t=0 , when the pendulum is exactly in the middle of its swing, the bob is 5 cm 5 \mathrm{~cm} away from the wall. The bob reaches the closest point to the wall, which is 3 cm 3 \mathrm{~cm} from the wall, 11 second later.\newlineFind D(t) D(t) .\newlinet t should be in radians.\newlineD(t)= D(t)=\square
  1. Initial Position Calculation: The pendulum is in the middle of its swing at t=0t=0, so the distance from the wall is the average of the maximum and minimum distances. This is the value of dd in the equation.
  2. Amplitude Calculation: Since the pendulum is 5cm5\,\text{cm} from the wall at t=0t=0, d=5d=5.
  3. Period Calculation: One second later, the pendulum is at its closest point to the wall, which is 3cm3\,\text{cm}. This means the amplitude aa is the difference between the average distance and the closest distance, so a=5cm3cm=2cma=5\,\text{cm} - 3\,\text{cm} = 2\,\text{cm}.
  4. Angular Frequency Calculation: The pendulum reaches its closest point to the wall 11 second later, which is a quarter of the period of the sinusoidal function. Therefore, the period TT is 44 seconds.
  5. Sinusoidal Function Determination: To convert the period TT into radians, we use the formula T=2π/bT = 2\pi / b, where bb is the angular frequency in radians per second. Solving for bb gives us b=2π/Tb = 2\pi / T.
  6. Sinusoidal Function Determination: To convert the period TT into radians, we use the formula T=2π/bT=2\pi/b, where bb is the angular frequency in radians per second. Solving for bb gives us b=2π/Tb=2\pi/T.Substitute TT with 44 seconds to find bb: b=2π/4=π/2b=2\pi/4=\pi/2 radians per second.
  7. Sinusoidal Function Determination: To convert the period TT into radians, we use the formula T=2π/bT=2\pi/b, where bb is the angular frequency in radians per second. Solving for bb gives us b=2π/Tb=2\pi/T.Substitute TT with 44 seconds to find bb: b=2π/4=π/2b=2\pi/4=\pi/2 radians per second.Now we have all the parameters for the sinusoidal function: a=2a=2cm, T=2π/bT=2\pi/b00 radians per second, and T=2π/bT=2\pi/b11cm. The function T=2π/bT=2\pi/b22 is therefore T=2π/bT=2\pi/b33.

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