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A marine biologist measured one fish that was 56\frac{5}{6} of a foot long and a second fish that was 16\frac{1}{6} of a foot long. How much longer was the first fish?\newlineWrite your answer as a fraction or as a whole or mixed number.\newline____\_\_\_\_ feet

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Q. A marine biologist measured one fish that was 56\frac{5}{6} of a foot long and a second fish that was 16\frac{1}{6} of a foot long. How much longer was the first fish?\newlineWrite your answer as a fraction or as a whole or mixed number.\newline____\_\_\_\_ feet
  1. Calculate difference in length: Calculate the difference in length between the first and second fish. \newline5616=46\frac{5}{6} - \frac{1}{6} = \frac{4}{6} \newlineSimplify 46\frac{4}{6} to 23\frac{2}{3}.

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Posted 3 months ago