A big cruise ship dropped anchor off the Caribbean island of Antigua. The heavy anchor dropped into the water at a rate of 2.5 meters per second. After 45 seconds, the anchor was 40 meters below the water's surface. From what height (above the water's surface) was the anchor released? □ meters How long did it take the anchor to reach the water's surface? □ seconds

Question

A big cruise ship dropped anchor off the Caribbean island of Antigua. The heavy anchor dropped into the water at a rate of 2.5 meters per second. After 45 seconds, the anchor was 40 meters below the water's surface. From what height (above the water's surface) was the anchor released?  □ meters How long did it take the anchor to reach the water's surface? □ seconds

Bytelearn · Accepted Answer

Calculate Total Distance: First, we need to calculate the total distance the anchor traveled in 45 seconds at a rate of 2.5 meters per second. Distance = Speed × Time Distance = 2.5 meters/second × 45 seconds Distance = 112.5 metersFind Height Above Surface: Now we know the anchor is 40 meters below the water's surface after traveling 112.5 meters. To find the height from which the anchor was released, we subtract the 40 meters from the total distance. Height above water's surface = Total distance - Distance below water's surface Height above water's surface = 112.5 meters - 40 meters Height above water's surface = 72.5 metersCalculate Time to Reach Surface: To find out how long it took the anchor to reach the water's surface, we divide the height above water's surface by the rate of descent. Time to reach water's surface = Height above water's surface / Rate of descent Time to reach water's surface = 72.5 meters / 2.5 meters/second Time to reach water's surface = 29 seconds

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