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Let’s check out your problem:

Which of the following is equal to 
x(x^(2)+9) ?
Choose 1 answer:
(A) 
x^(2)+x+9
(B) 
x^(2)+9x
(C) 
x^(3)+9
(D) 
x^(3)+9x

Which of the following is equal to x(x2+9) x\left(x^{2}+9\right) ?\newlineChoose 11 answer:\newline(A) x2+x+9 x^{2}+x+9 \newline(B) x2+9x x^{2}+9 x \newline(C) x3+9 x^{3}+9 \newline(D) x3+9x x^{3}+9 x

Full solution

Q. Which of the following is equal to x(x2+9) x\left(x^{2}+9\right) ?\newlineChoose 11 answer:\newline(A) x2+x+9 x^{2}+x+9 \newline(B) x2+9x x^{2}+9 x \newline(C) x3+9 x^{3}+9 \newline(D) x3+9x x^{3}+9 x
  1. Distribute xx: Distribute xx across the terms inside the parentheses.\newlineWe apply the distributive property: a(b+c)=ab+aca(b + c) = ab + ac.\newlineHere, a=xa = x, b=x2b = x^2, and c=9c = 9.\newlineSo, x(x2+9)=xx2+x9x(x^2 + 9) = x\cdot x^2 + x\cdot 9.
  2. Apply distributive property: Simplify the expression.\newlinexx2x \cdot x^2 is xx raised to the power of (1+2)(1+2) because when we multiply powers with the same base, we add the exponents.\newlinexx2=x(1+2)=x3x \cdot x^2 = x^{(1+2)} = x^3.\newlinex9x \cdot 9 is simply 9x9x.\newlineSo, x(x2+9)=x3+9xx(x^2 + 9) = x^3 + 9x.