Q. Which of the following graphs in the xy-plane have −3 and 5 as all of their distinct zeros for −6≤x≤6 ?
Problem Understanding: Understand the problem.We need to find the graphs that have −3 and 5 as their only zeros within the interval −6≤x≤6. This means that the graph should touch or cross the x-axis at x=−3 and x=5, and not at any other point within the given interval.
General Form of the Polynomial: Determine the general form of the polynomial.A polynomial that has −3 and 5 as zeros can be written as f(x)=a(x+3)(x−5), where a is a non-zero constant. The value of a will affect the width and direction of the graph but not the zeros.
Additional Requirements: Check for additional requirements.Since the problem only specifies that −3 and 5 are the distinct zeros and does not mention any other conditions, any graph of the form f(x)=a(x+3)(x−5) with a=0 will satisfy the condition as long as it does not cross the x-axis at any other point within the interval −6≤x≤6.
Behavior at the Zeros: Determine the behavior of the graph at the zeros.At x=−3, the graph should either touch or cross the x-axis, and the same goes for x=5. If a > 0, the graph will open upwards, and if a < 0, the graph will open downwards.
Behavior Outside the Zeros: Verify the behavior of the graph outside the zeros. For x < -3, the graph should be above the x-axis if a > 0 and below the x-axis if a < 0. For -3 < x < 5, the graph should be below the x-axis if a > 0 and above the x-axis if a < 0. For x > 5, the graph should be above the x-axis if a > 0 and below the x-axis if a < 0.
Graph Characteristics: Conclude the characteristics of the graph.The graph of f(x)=a(x+3)(x−5) will have −3 and 5 as its zeros, and it will not have any other zeros within the interval −6≤x≤6. The graph will either open upwards or downwards depending on the sign of a, but this does not affect the location of the zeros.