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What is the inverse of the function 
f(x)=3x-2 ?

f^(-1)(x)=

What is the inverse of the function \newlinef(x)=3x2?f(x)=3x-2 ?\newlinef1(x)=f^{-1}(x)=

Full solution

Q. What is the inverse of the function \newlinef(x)=3x2?f(x)=3x-2 ?\newlinef1(x)=f^{-1}(x)=
  1. Replace f(x)f(x) with yy: To find the inverse of the function f(x)=3x2f(x) = 3x - 2, we first replace f(x)f(x) with yy. So, we have y=3x2y = 3x - 2.
  2. Swap xx and yy: Next, we swap xx and yy to find the inverse. This gives us x=3y2x = 3y - 2.
  3. Solve for y: Now, we solve for y to get the inverse function. Add 22 to both sides of the equation to isolate the term with y. This gives us x+2=3yx + 2 = 3y.
  4. Divide by 33: Divide both sides of the equation by 33 to solve for y. This gives us y=x+23y = \frac{x + 2}{3}.
  5. Replace yy with f1(x)f^{-1}(x): Replace yy with f1(x)f^{-1}(x) to denote the inverse function. So, the inverse function is f1(x)=x+23f^{-1}(x) = \frac{x + 2}{3}.

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