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What is the inverse of the function
\newline
f
(
x
)
=
3
x
−
2
?
f(x)=3x-2 ?
f
(
x
)
=
3
x
−
2
?
\newline
f
−
1
(
x
)
=
f^{-1}(x)=
f
−
1
(
x
)
=
View step-by-step help
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Math Problems
Calculus
Find derivatives using the chain rule I
Full solution
Q.
What is the inverse of the function
\newline
f
(
x
)
=
3
x
−
2
?
f(x)=3x-2 ?
f
(
x
)
=
3
x
−
2
?
\newline
f
−
1
(
x
)
=
f^{-1}(x)=
f
−
1
(
x
)
=
Replace
f
(
x
)
f(x)
f
(
x
)
with
y
y
y
:
To find the inverse of the function
f
(
x
)
=
3
x
−
2
f(x) = 3x - 2
f
(
x
)
=
3
x
−
2
, we first replace
f
(
x
)
f(x)
f
(
x
)
with
y
y
y
. So, we have
y
=
3
x
−
2
y = 3x - 2
y
=
3
x
−
2
.
Swap
x
x
x
and
y
y
y
:
Next, we swap
x
x
x
and
y
y
y
to find the inverse. This gives us
x
=
3
y
−
2
x = 3y - 2
x
=
3
y
−
2
.
Solve for y:
Now, we solve for y to get the inverse function. Add
2
2
2
to both sides of the equation to isolate the term with y. This gives us
x
+
2
=
3
y
x + 2 = 3y
x
+
2
=
3
y
.
Divide by
3
3
3
:
Divide both sides of the equation by
3
3
3
to solve for y. This gives us
y
=
x
+
2
3
y = \frac{x + 2}{3}
y
=
3
x
+
2
.
Replace
y
y
y
with
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
:
Replace
y
y
y
with
f
−
1
(
x
)
f^{-1}(x)
f
−
1
(
x
)
to denote the inverse function. So, the inverse function is
f
−
1
(
x
)
=
x
+
2
3
f^{-1}(x) = \frac{x + 2}{3}
f
−
1
(
x
)
=
3
x
+
2
.
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Find the derivative of
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\newline
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′
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=
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′
(
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)
=
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Find the derivative of
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(
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.
\newline
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x
)
=
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Find the derivative of
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\newline
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\newline
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′
(
x
)
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Question
Find the derivative of
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(
x
)
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(
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)
.
\newline
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(
x
)
=
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+
3
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f
(
x
)
=
x
+
3
\newline
f
′
(
x
)
=
f'(x) =
f
′
(
x
)
=
______
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Posted 1 year ago
Question
Find the derivative of
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(
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)
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(
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.
\newline
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)
=
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\newline
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′
(
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=
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