The inclination (tilt) of an amusement park ride is accelerating at a rate of 2160(" degrees ")/(min^(2)). What is the ride's acceleration rate in (" degrees ")/(s^(2)) ? (" degrees ")/(s^(2))

Convert to seconds: To convert the acceleration rate from degrees per minute squared to degrees per second squared, we need to know how many seconds are in one minute. There are 60 seconds in one minute. Therefore, to convert from per minute squared to per second squared, we need to divide the given rate by 60 squared (since there are 60 seconds in a minute and we are dealing with a squared quantity). Calculation: $ \frac{2160 \text{ degrees/min}^2}{60^2} $Perform calculation: Now, we perform the calculation. $ \frac{2160}{60^2} = \frac{2160}{3600} $Simplify fraction: Simplify the fraction by dividing 2160 by 3600. $ \frac{2160}{3600} = 0.6 $ So, the ride's acceleration rate is 0.6 degrees per second squared.

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The inclination (tilt) of an amusement park ride is accelerating at a rate of
2160(" degrees ")/(min^(2)).
What is the ride's acceleration rate in
(" degrees ")/(s^(2)) ?

(" degrees ")/(s^(2))

The inclination (tilt) of an amusement park ride is accelerating at a rate of $2160 \frac{\text { degrees }}{\min ^{2}}$ . $\newline$ What is the ride's acceleration rate in $\frac{\text { degrees }}{\mathrm{s}^{2}}$ ? $\newline$ $\frac{\text { degrees }}{\mathrm{s}^{2}}$

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Algebra 1

Convert rates and measurements: customary units

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Q. The inclination (tilt) of an amusement park ride is accelerating at a rate of

2160 \frac{\text { degrees }}{\min ^{2}}

\newline

What is the ride's acceleration rate in

\frac{\text { degrees }}{\mathrm{s}^{2}}

\newline

\frac{\text { degrees }}{\mathrm{s}^{2}}

Convert to seconds: To convert the acceleration rate from degrees per minute squared to degrees per second squared, we need to know how many seconds are in one minute. $\newline$ There are $60$ seconds in one minute. Therefore, to convert from per minute squared to per second squared, we need to divide the given rate by $60$ squared (since there are $60$ seconds in a minute and we are dealing with a squared quantity). $\newline$ Calculation: $\frac{2160 \text{ degrees/min}^2}{60^2}$
Perform calculation: Now, we perform the calculation. $\newline$ $\frac{2160}{60^2} = \frac{2160}{3600}$
Simplify fraction: Simplify the fraction by dividing $2160$ by $3600$ . $\newline$ $\frac{2160}{3600} = 0.6$ $\newline$ So, the ride's acceleration rate is $0$ . $6$ degrees per second squared.