Solve the following equation for z. sqrt((53+5z)/(7))=2 z=

Square both sides: Square both sides of the equation to eliminate the square root. (sqrt((53+5z)/7))^2 = 2^2 (53+5z)/7 = 4Multiply by 7: Multiply both sides of the equation by 7 to isolate the term with z. 7 * ((53+5z)/7) = 4 * 7 53+5z = 28Subtract 53: Subtract 53 from both sides of the equation to solve for 5z. 53+5z - 53 = 28 - 53 5z = -25Divide by 5: Divide both sides of the equation by 5 to solve for z. 5z/5 = -25/5 z = -5

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve the following equation for
z.

sqrt((53+5z)/(7))=2

z=

Solve the following equation for $z$ . $\newline$ $\sqrt{\frac{53+5 z}{7}}=2$ $\newline$ $z=$

View step-by-step help

Home

Math Problems

Precalculus

Solve radical equations

Full solution

Q. Solve the following equation for

z

\newline

\sqrt{\frac{53+5 z}{7}}=2

\newline

z=

Square both sides: Square both sides of the equation to eliminate the square root. $\newline$ $(\sqrt{(53+5z)/7})^2 = 2^2$ $\newline$ $(53+5z)/7 = 4$
Multiply by $7$ : Multiply both sides of the equation by $7$ to isolate the term with z. $\newline$ $7 \times \left(\frac{53+5z}{7}\right) = 4 \times 7$ $\newline$ $53+5z = 28$
Subtract $53$ : Subtract $53$ from both sides of the equation to solve for $5z$ . $\newline$ $53+5z - 53 = 28 - 53$ $\newline$ $5z = -25$
Divide by $5$ : Divide both sides of the equation by $5$ to solve for $z$ . $\frac{5z}{5} = \frac{-25}{5}$ $z = -5$