Solve the equation. (1)/(8)+c=(4)/(5) c=

Isolate the variable c: Isolate the variable c on one side of the equation. To do this, we need to subtract (1/8) from both sides of the equation. (1/8) + c - (1/8) = (4/5) - (1/8) c = (4/5) - (1/8)Find a common denominator: Find a common denominator for the fractions to subtract them. The common denominator for 5 and 8 is 40. c = (4/5) * (8/8) - (1/8) * (5/5) c = (32/40) - (5/40)Subtract the fractions: Subtract the fractions. Now that we have a common denominator, we can subtract the numerators. c = (32/40) - (5/40) c = (32 - 5)/40 c = 27/40

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Solve the equation.

(1)/(8)+c=(4)/(5)

c=

Solve the equation. $\newline$ $\frac{1}{8}+c=\frac{4}{5}$ $\newline$ $c=$

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Algebra 1

Solve linear equations: mixed review

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Q. Solve the equation.

\newline

\frac{1}{8}+c=\frac{4}{5}

\newline

c=

Isolate the variable c: Isolate the variable $c$ on one side of the equation. $\newline$ To do this, we need to subtract $\frac{1}{8}$ from both sides of the equation. $\newline$ $\frac{1}{8} + c - \frac{1}{8} = \frac{4}{5} - \frac{1}{8}$ $\newline$ $c = \frac{4}{5} - \frac{1}{8}$
Find a common denominator: Find a common denominator for the fractions to subtract them. $\newline$ The common denominator for $5$ and $8$ is $40$ . $\newline$ $c = \left(\frac{4}{5}\right) \cdot \left(\frac{8}{8}\right) - \left(\frac{1}{8}\right) \cdot \left(\frac{5}{5}\right)$ $\newline$ $c = \left(\frac{32}{40}\right) - \left(\frac{5}{40}\right)$
Subtract the fractions: Subtract the fractions. $\newline$ Now that we have a common denominator, we can subtract the numerators. $\newline$ c = $\frac{32}{40}$ - $\frac{5}{40}$ $\newline$ c = $\frac{32 - 5}{40}$ $\newline$ c = $\frac{27}{40}$